在列中编辑字符串时,Pandas Dataframe“SettingWithCopyWarning:”

时间:2018-01-30 22:28:45

标签: pandas dataframe

所以我有这个数据框:

dfprices = pd.DataFrame(价格)

dfprices

 pd.Dataframe = (             
         price         symbol
0        0.10566500    ETHBTC
1        0.01643000    LTCBTC
2        0.00112080    BNBBTC
3        0.01423200    NEOBTC
4        0.00030000    123456
5        0.03393500   QTUMETH
6        0.01077400    EOSETH
7        0.00022600    SNTETH
8        0.00630600    BNTETH
9        0.14548000    BCCBTC
10       0.00599900    GASBTC
11       0.01059800    BNBETH
12   10294.77000000   BTCUSDT
13    1089.99000000   ETHUSDT
14       0.00142500    HSRBTC )

从此我想

  1. 仅选择comlumn“symbol”中的文本以“BTC”结尾的行。
  2. 接下来我想从'symbol'列中的字符串中删除'BTC'
  3. 为此,我使用了以下代码:

    dfcleanprices = dfprices[dfprices['symbol'].str[-3:]=="BTC"]
    dfcleanprices['symbol'] = dfcleanprices['symbol'].str[:-3]
    

    我想要的结果是:

    dfcleanprices

      pd.Dataframe = (          
             price         symbol
        0    0.10566500    ETH
        1    0.01643000    LTC
        2    0.00112080    BNB
        3    0.01423200    NEO
        9    0.14548000    BCC
        10   0.00599900    GAS
        14   0.00142500    HSR
        19   0.00105000    MCO
        20   0.00324080    WTC
        22   0.00009404    LRC
        24   0.00358700   QTUM)
    

    但是通过执行第二个语句会显示警告:

    SettingWithCopyWarning: 
    A value is trying to be set on a copy of a slice from a DataFrame.
    Try using .loc[row_indexer,col_indexer] = value instead
    See the caveats in the documentation: http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-view-versus-copy
      from binance.client import Client
    

    我尝试了很多,但我真的需要帮助:)

0 个答案:

没有答案
相关问题