Question

我需要2个表来验证某些信息，例如：

表A（GTM_LICENSE）：

License ID (PK) - License Category
123 - PURCHASE
456 - SALES

表B（GTM_LICENSE_INVOLVED_PARTY）：

License ID (PK) - Involved Party Type
123 - SUPPLIER X
456 - CUSTOMER X

但是，我需要验证以下内容：购买许可证必须始终至少有一个供应商记录。销售许可证必须始终至少有一个CUSTOMER记录。

我可以执行2个不同的查询，甚至只能执行1个查询，一次检查这两个条件。没关系。但是，如果条件为真（购买许可证有供应商或销售许可证有客户），我的预期结果将为“1”，如果条件为假，则为null。

我正在尝试运行以下查询，但这对我不起作用。

SELECT 1 FROM GTM_LICENSE L
INNER JOIN GTM_LICENSE_INVOLVED_PARTY LI
ON LI.LICENSE_GID = L.LICENSE_GID 
WHERE LI.INVOLVED_PARTY_QUAL_GID IN ('CUSTOMER','SUPPLIER') 
  AND L.LICENSE_CATEGORY_GID IN ('SALES','PURCHASE')
GROUP BY L.LICENSE_GID 
HAVING COUNT(*) > 0

如何使用Oracle SQL执行此操作？有什么建议吗？

由于

Answer 1

select l.license_gid,
  l.license_category_gid,
  (select max(1) from gtm_license_involved_party li
         where li.license_gid = l.license_gid
           and ((li.involved_party_qual_gid = 'CUSTOMER' 
                 and l.license_category_gid = 'SALES')
                or (li.involved_party_qual_gid = 'SUPPLIER' 
                    and l.license_category_gid = 'PURCHASE'))
     ) valid_party
from gtm_license l
;

Answer 2

我相信这会让您获得不符合要求的许可证列表：

SELECT L.LICENSE_GID
FROM GTM_LICENSE L LEFT OUTER JOIN GTM_LICENSE_INVOLVED_PARTY LI
    ON LI.LICENSE_GID = L.LICENSE_GID AND
        (
                L.LICENSE_CATEGORY_GID = 'PURCHASE'
            AND LI.INVOLVED_PARTY_QUAL_GID = 'SUPPLIER'
        OR 
                L.LICENSE_CATEGORY_GID = 'SALES'
            AND LI.INVOLVED_PARTY_QUAL_GID = 'CUSTOMER'
        )
WHERE
GROUP BY L.LICENSE_GID 
HAVING COUNT(LI.LICENSE_GID) = 0;

这可能比复杂的连接条件更直接：

SELECT L.LICENSE_GID
FROM GTM_LICENSE L
WHERE NOT EXISTS (
    SELECT 1 FROM GTM_LICENSE_INVOLVED_PARTY LI
    WHERE LI.LICENSE_GID = L.LICENSE_GID AND
        (
                L.LICENSE_CATEGORY_GID = 'PURCHASE'
            AND LI.INVOLVED_PARTY_QUAL_GID = 'SUPPLIER'
        OR 
                L.LICENSE_CATEGORY_GID = 'SALES'
            AND LI.INVOLVED_PARTY_QUAL_GID = 'CUSTOMER'
        )
);

这将为您提供包含每个许可证指标的结果集。它与kfinity的答案几乎相同。我没有使用聚合函数折叠到标量值，而是使用可以说更具可读性的case表达式：

SELECT L.LICENSE_GID
    CASE WHEN NOT EXISTS (
        SELECT 1 FROM GTM_LICENSE_INVOLVED_PARTY LI
        WHERE LI.LICENSE_GID = L.LICENSE_GID AND
            (
                    L.LICENSE_CATEGORY_GID = 'PURCHASE'
                AND LI.INVOLVED_PARTY_QUAL_GID = 'SUPPLIER'
            OR 
                    L.LICENSE_CATEGORY_GID = 'SALES'
                AND LI.INVOLVED_PARTY_QUAL_GID = 'CUSTOMER'
            )
    ) THEN 1 ELSE NULL END AS INDICATOR
FROM GTM_LICENSE L;

Oracle SQL在两个表之间进行检查

2 个答案: