Question

如何让'users'-table中的人成为'notes'-table中笔记的拥有者？ e.g：

我希望表'users'中的id“1”成为表'notes'中id“2”的所有者。

编辑：我正在使用“用户”的登录会话

'用户'是：

CREATE TABLE `users` (
  `id` int NOT NULL AUTO_INCREMENT,
  `username` varchar(30) NOT NULL DEFAULT '',
  `email` varchar(50) NOT NULL DEFAULT '',
  `password` varchar(70) NOT NULL DEFAULT '',
  PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

和'notes'是：

CREATE TABLE `notes` (
  `id` int NOT NULL AUTO_INCREMENT,
  `user_id` int NOT NULL,
  `title` text NOT NULL,
  `content` text NOT NULL,
  `created` TIMESTAMP DEFAULT now(),
  `edited` TIMESTAMP DEFAULT now() ON UPDATE now(),
  PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

这是我的'注释'代码（如何在顶部说明中包含'用户'）：

public function fetchNotes($id = null) {
    $stmt = $this->pdo->prepare('SELECT title, content FROM notes WHERE id = :id');
    $stmt->bindParam(':id', $id);
    $stmt->execute();
}

public function create($title, $content) {
    $stmt = $this->pdo->prepare('INSERT INTO notes (title, content, created) VALUES (:title, :content, null)');
    $stmt->bindParam(':title', $title);
    $stmt->bindParam(':content', $content);
    $stmt->execute();
}

public function delete($id) {
    $stmt = $this->pdo->prepare('DELETE FROM notes WHERE id = :id');
    $stmt->bindParam(':id', $id);
    $stmt->execute();
}

public function edit($id, $title, $content) {
    $stmt = $this->pdo->prepare('UPDATE notes SET title = :title, content = :content WHERE id = :id');
    $stmt->bindParam(':id', $id);
    $stmt->bindParam(':title', $title);
    $stmt->bindParam(':content', $content);
    $stmt->execute();
}

Answer 1

解决方案：创建名为＆＃34; user_id＆＃34;的列并使其等于＆＃34; id＆＃34; ＆＃39;用户＆＃39; -table。然后，如果您希望它检查SESSION [＆＃39; id＆＃39;] == row [＆＃39; user_id＆＃39;]，请使用if命令进行检查...

如何在“笔记”中让用户成为“笔记”中笔记的“用户”所有者？ PHP MySQL

1 个答案: