Question

我正在尝试用C＃实现堆栈。

问题是Display方法正在打印我添加到堆栈的所有整数的ascii值。例如。添加到堆栈的3个打印为51,5和53

我甚至尝试过Console.WriteLine（ele.value.GetType（）），它将类型返回为System.Int32

using System;
class Program
{
static Stack root, top;
static void Main(string[] args)
{
    Console.WriteLine("This is numeric stack.\n1: Push to stack\n2: Pop from stack");
    int response = Convert.ToInt16(Console.ReadLine());
    if(response == 1)
        Push();
}

static void Push()
{
    Console.WriteLine("Enter your number...");
    int val = Console.Read();
    if(root == null)
    {
        root = new Stack(val);
        top = root;
    }
    else
    {
        top.top = new Stack(val);
    }
    Display();
}

static void Display()
{
    Stack ele = root;
    while (ele != null)
    {
        int count = 1;
        Console.WriteLine(count + ": " + ele.value);
        count++;
        ele = ele.top;
    }
}
}

class Stack
{
    public int value;
    public Stack top;
    public Stack(int val) => this.value = val;
}

Answer 1

问题的输出不是问题。这是输入。 Console.Read方法专门返回它读取的字符的Unicode值。如果您要将用户输入的值存储为int，请致电Console.ReadLine并通过调用int将结果转换为Convert.ToInt32，或者将结果与{{1}合并}}

WriteLine隐式打印int的ascii值

1 个答案: