Question

考虑一个例子，我有两个实体，如下所示

Attribute.java

@Entity
     @Table(name = "attribute")
     public class Attribute {
        @Id
        @GeneratedValue(strategy=GenerationType.IDENTITY)
        @Getter private Long id;

    @Column(name="name")
    @Getter private String name;    

    @Column(name = "source")
    @Getter private String source;

    protected Attribute(){}
    public Attribute(final String name, final String source) {
        this.name = name;
        this.source = source;
    }


}

AttributeGroup.java

    @Column(name="name")
    @Getter private String name;    

    @Column(name = "source")
    @Getter private String source;

    protected Attribute(){}
    public Attribute(final String name, final String source) {
        this.name = name;
        this.source = source;
    }

两个存储库

AttributeRepository.java

@Entity @Table(name = "attribute_group") public class AttributeGroup {

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Getter private Long id;

    @Column(name="name")
    @Getter private String name;

    @Column(name = "value")
    @Getter private String value;

    @Getter
    @Column(name="attribute_id", nullable=false)
    protected Long attributeId;

    @Getter
    @OneToOne(optional=true, fetch = FetchType.EAGER)
    @JoinColumn(name="attribute_id",  updatable=false, insertable=false,  referencedColumnName="id")
    private Attribute attribute;

    protected AttributeGroup(){}
}

AttributeGroupRepository.java

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY)
    @Getter private Long id;

    @Column(name="name")
    @Getter private String name;

    @Column(name = "value")
    @Getter private String value;

    @Getter
    @Column(name="attribute_id", nullable=false)
    protected Long attributeId;

    @Getter
    @OneToOne(optional=true, fetch = FetchType.EAGER)
    @JoinColumn(name="attribute_id",  updatable=false, insertable=false,  referencedColumnName="id")
    private Attribute attribute;

    protected AttributeGroup(){}
}

AttributeGroupRepositoryTest.java

public interface AttributeRepository{}

xml文件

public interface AttributeGroupRepository {

/**
 * find list of Groups by attribute name
 * @param attribute
 * @return
 */
List<AttributeGroup> findByAttribute(Attribute attribute);


}

以上测试用例抛出异常

/**
 * find list of Groups by attribute name
 * @param attribute
 * @return
 */
List<AttributeGroup> findByAttribute(Attribute attribute);

由于此测试依赖于属性存储库，因为Junit是单元测试用例，我不想使用属性存储库。

是否有其他方法可以模拟其他存储库数据？

Answer 1

我找到了不使用其他存储库的方法，我们可以如何执行测试用例。

替换以下行：

List<AttributeGroup> groups = groupRepository.findByAttribute(attribute);

与

List<AttributeGroup> groups = groupRepository.findByAttributeNameAndAttributeSource("Data","abc");

Answer 2

您正在搜索未在存储库中保留的对象，请先从AttributeRepository中找到该属性，然后在属性组存储库中搜索返回的属性！

Attribute attribute=attributeRepository.findByNameAndSource("Data",Source);
if(attribute!=null){
   List<AttributeGroup> groups = groupRepository.findByAttribute(attribute);
}

编写JPA存储库JUnit，其中一个存储库依赖于Other

2 个答案: