Question

map <int, char*> testmap;
testmap[1] = "123";
testmap[2] = "007";
map<int, char*>::iterator p;

for(p = my_map.begin(); p != my_map.end(); p++) {
int len = strlen(p); // error here, why? thanks
cout << len << endl;
  cout << p->first << " : ";
  cout << p->second << endl;
}

我在这个谎言上得到错误：int len = strlen（p），我想得到数组的长度。如何修复它？谢谢！

Answer 1

我猜你的意思是

strlen(p->second);

Answer 2

更好用std string：

map <int, std::string> testmap;
testmap[1] = "123";
testmap[2] = "007";
map<int, std::string>::iterator p;

for(p = testmap.begin(); p != testmap.end(); p++) {
    int len = p->second.size();
    cout << len << endl;
    cout << p->first << " : ";
    cout << p->second << endl;
}

Answer 3

strlen(p->second)

p是一个迭代器

Answer 4

map <int, char*> testmap;
testmap[1] = "123";
testmap[2] = "007";
map<int, char*>::iterator p;

for(p = my_map.begin(); p != my_map.end(); p++) {
    int len = std::iterator_traits<p>::value_type.size();
    cout << len << endl;
    cout << p->first << " : ";
    cout << p->second << endl;
}

Answer 5

p是对键值的迭代器。你只需要价值。

C ++，迭代器问题

5 个答案: