有这样的表：
`id` `race_day` `racer_nr` `racer_name` `racer_class` `start_time` `arrive_time` `spent_time` `total` `yellow_card` `bonus` `penalties` `comment`
1 1 313 'racer name 1' '' '2018-02-04 10:00:00' '2018-02-04 10:57:00' '00:57:00' '00:57:00' 0 0 0 ''
2 1 135 'racer name 2' '' '2018-02-04 10:00:00' '2018-02-04 13:59:55' '03:59:55' '03:59:55' 0 0 5 ''
3 1 55 'racer name 3' '' '2018-02-04 10:00:00' '2018-02-04 11:59:50' '01:59:50' '01:59:50' 0 0 0 ''
4 1 315 'racer name 4' '' '2018-02-04 10:00:00' '2018-02-04 10:01:40' '00:01:40' '00:01:40' 0 20 3600 ''
17 2 313 'racer name 1' '' '2018-02-05 10:00:00' '2018-02-05 10:57:00' '00:57:00' '00:57:00' 0 0 0 ''
18 2 135 'racer name 2' '' '2018-02-05 10:00:00' '2018-02-05 13:59:55' '03:59:55' '03:59:55' 0 0 0 ''
19 2 55 'racer name 3' '' '2018-02-05 10:00:00' '2018-02-05 11:59:50' '01:59:50' '01:59:50' 0 0 0 ''
20 2 315 'racer name 4' '' '2018-02-05 10:00:00' '2018-02-05 10:01:40' '00:01:40' '00:01:40' 0 0 0 ''
21 3 313 'racer name 1' '' '2018-02-06 10:00:00' '2018-02-06 10:57:00' '00:57:00' '00:57:00' 0 0 0 ''
22 3 135 'racer name 2' '' '2018-02-06 10:00:00' '2018-02-06 13:59:55' '03:59:55' '03:59:55' 0 0 0 ''
23 3 55 'racer name 3' '' '2018-02-06 10:00:00' '2018-02-06 11:59:50' '01:59:50' '01:59:50' 0 0 0 ''
24 3 315 'racer name 4' '' '2018-02-06 10:00:00' '2018-02-06 10:01:40' '00:01:40' '00:01:40' 0 15 3600 ''
25 4 313 'racer name 1' '' '2018-02-07 10:00:00' '2018-02-07 10:57:00' '00:57:00' '00:57:00' 0 0 0 ''
26 4 135 'racer name 2' '' '2018-02-07 10:00:00' '2018-02-07 13:59:55' '03:59:55' '03:59:55' 0 0 0 ''
27 4 55 'racer name 3' '' '2018-02-07 10:00:00' '2018-02-07 11:59:50' '01:59:50' '01:59:50' 0 0 0 ''
28 4 315 'racer name 4' '' '2018-02-07 10:00:00' '2018-02-07 10:01:40' '00:01:40' '00:01:40' 0 0 0 ''
29 5 313 'racer name 1' '' '2018-02-08 10:00:00' '2018-02-08 10:57:00' '00:57:00' '00:57:00' 0 0 0 ''
30 5 135 'racer name 2' '' '2018-02-08 10:00:00' '2018-02-08 13:59:55' '03:59:55' '03:59:55' 0 0 0 ''
31 5 55 'racer name 3' '' '2018-02-08 10:00:00' '2018-02-08 11:59:50' '01:59:50' '01:59:50' 0 0 0 ''
32 5 315 'racer name 4' '' '2018-02-08 10:00:00' '2018-02-08 10:01:40' '00:01:40' '00:01:40' 0 0 0 ''
和这样的SQL查询：
SELECT
id,
race_day,
racer_nr,
racer_name,
arrive_time,
spent_time,
sec_to_time(SUM(time_to_sec(spent_time)+penalties-bonus)) AS total_time_spent,
SUM(penalties) AS total_penalties,
SUM(bonus) as total_bonus,
yellow_card
FROM `race_days`
WHERE
`race_day` = 1 OR `race_day` = 2 OR `race_day` = 3 OR `race_day` = 4 OR `race_day` = 5
GROUP BY racer_nr
ORDER BY total_time_spent ASC
我得到了我想要的所有数据.. 但如果我想获得不同race_day的到达时间，我只会得到第一个约会（race_day = 1）
即。 计算race_day = 2的总数我的查询将是这样的：
SELECT
id,
race_day,
racer_nr,
racer_name,
arrive_time,
spent_time,
sec_to_time(SUM(time_to_sec(spent_time)+penalties-bonus)) AS total_time_spent,
SUM(penalties) AS total_penalties,
SUM(bonus) as total_bonus,
yellow_card
FROM `race_days`
WHERE
`race_day` = 1 OR `race_day` = 2
GROUP BY racer_nr
ORDER BY total_time_spent ASC
我无法获得race_day = 2的到达时间（也是和start_time）。
所以我想要的race_day = 2结果应该是这样的：
`id`, `race_day`, `racer_nr`, `racer_name`, `arrive_time`, `spent_time`, `total_time_spent`, `total_penalties`, `total_bonus`, `yellow_card`
4, 1, 315, 'racer name 4', '2018-02-05 10:01:40', '00:01:40', '01:03:00', '3600', '20', 0
1, 1, 313, 'racer name 1', '2018-02-05 10:57:00', '00:57:00', '01:54:00', '0', '0', 0
3, 1, 55, 'racer name 3', '2018-02-05 11:59:50', '01:59:50', '03:59:40', '0', '0', 0
2, 1, 135, 'racer name 2', '2018-02-05 13:59:55', '03:59:55', '07:59:55', '5', '0', 0
任何建议都将不胜感激
答案 0 :(得分：0)
select子句应始终与聚合查询中的group by子句匹配。所以你应该从：
SELECT racer_nr,
sec_to_time(SUM(time_to_sec(spent_time)+penalties-bonus)) AS total_time_spent,
SUM(penalties) AS total_penalties,
SUM(bonus) as total_bonus
FROM race_days rd
WHERE race_day in (1, 2, 3, 4, 5)
GROUP BY racer_nr
ORDER BY total_time_spent ASC;
我不知道你想要的其他（非聚合）列是什么。但是，它们应该是聚合函数或group by子句中的参数。
例如，如果您想为每个race_day分别设置一行，您可以执行以下操作：
SELECT racer_nr, race_day, MIN(arrive_time),
sec_to_time(SUM(time_to_sec(spent_time)+penalties-bonus)) AS total_time_spent,
SUM(penalties) AS total_penalties,
SUM(bonus) as total_bonus
FROM race_days rd
WHERE race_day in (1, 2, 3, 4, 5)
GROUP BY racer_nr, race_day
ORDER BY total_time_spent ASC;