PHP时间戳比较

Question

$today      = mktime(0,0,0,2, 9, 2011);
$today >= $r['arrival_date'] // false
9 >= date('j', $r['arrival_date']) // true

$r['arival_date'] is 1297227600 [Feb 9, 2011 07:00]

Answer 1

简单：

$today = mktime(0,0,0,2, 9, 2011); // = 1297209600

和

$r['arival_date'] = 1297227600;

所以

1297227600 > 1297209600

因为

date('H',$r['arrival_date']); // 7
date('H',$today); // 0

Answer 2

为了扩展并解释Andre Matos的回答，mktime(0,0,0,2,9,2011);是00:00:00 Feb 9 2011，基本上是2月9日的第一个瞬间，到达日期是07:00:00 Feb 9 2011，7小时后，所以它是timestamp大于mktime创建的时间戳。

要检查时间戳是否在特定日期内，您可以通过以下几种方式检查：

//You can check by adding a day onto the timestamp for today, 24*60*60 is one days worth of seconds (86400 seconds)
if($r['arrival_date'] >= $today && $r['arrival_date'] <= $today + (24*60*60))

//Or you can mktime for tomorrow too.  
$tomorrow = mktime(0,0,0,2,10,2011);
if($r['arrival_date'] >= $today && $r['arrival_date'] <= $tomorrow)

//Or you could check the way you have up there, by running it through date and checking if one is equivalent to another
//Or you could do strtotime in there somewhere, or whatever

这只是最简单的几个。基本上由于时间戳下降到第二个（特别是00:00:00 Jan 1 1970 UTC后的秒数），你将不得不按范围检查它们。