Question

我的计算器配置依赖于＆＃39;视图（GUI）的定义如下（然后在当前上下文中解析）：

    Dependencies.register<IView, View>(
        "standardView"
    );

    //Register: calculator release configuration
    Dependencies.register<ICalculator, Calculator>(
        "releaseCalculator",
        (new InjectionProperty(
            "IView", 
            Dependencies.resolve<IView>("standardView")
        ))
    );

    //Resolve:
    Calculator theCalculator = (Calculator)Dependencies.resolve<ICalculator>(
        "releaseCalculator"
    );

其中Dependencies是IUnityContainer的包装器。

Calculator中的注入点是：

private IView view;
[Dependency]
public IView IView{
    get{return view;}
    set{view = value;}
}

如果您希望看到Dependencies的定义，请注意它绝对等同于统一容器的投影，除非我已经延长了对终身经理的直接控制。

问题很简单;给定上述设置，属性IView在运行时解析为null。就好像Unity只是没有血腥的工作。

@Haukinger这里是包装器：

using System.Collections.Generic;
using Unity;
using Unity.Lifetime;
using Unity.Registration;


namespace Calculator.Utils
{
public static class Dependencies
{
    private static IUnityContainer graph;
    private static List<KeyValuePair<string, LifetimeManager>> lifetimeManagers;


    static Dependencies(){
        //container
        graph = new UnityContainer();
        //instance managers 1 per dependency instance (implementor)
        lifetimeManagers = new List<KeyValuePair<string, LifetimeManager>>();
    }


  //STATES:
    public static void register<I, P>(string alias, params InjectionMember[] injections)
    {
        ContainerControlledTransientManager newLM = new ContainerControlledTransientManager();
        lifetimeManagers.Add(new KeyValuePair<string, LifetimeManager>(
            alias,
            newLM
        ));
        graph.RegisterType(
            typeof(I),
            typeof(P),
            alias,
            newLM,
            injections
        );
    }

    //function is identitical to Resolve
    public static T resolve<T>(string alias)
    {
        return (T)graph.Resolve(typeof(T), alias);
    }

    public static void dispose(string alias)
    {
        LifetimeManager target = (ContainerControlledTransientManager)lifetimeManagers.Find((elem)=>(elem.Key.Equals(alias))).Value;
        target.Dispose();
    }
}

}

Answer 1

仅在您请求所有注册类型（即IView[] allViews）时才会注入命名注册。如果您只请求一个实例，那么您将收到默认注册，在您的情况下只有null，因为您没有默认注册。

删除名称（standardView）并将null作为参数name传递给RegisterType，您就可以了。

编辑：此代码在我的机器上正常运行

internal class Program
{
    static void Main( string[] args )
    {
        var container = new UnityContainer();
        container.RegisterType<IDependency, MyDependency>((string)null);
        var resolved = container.Resolve<Consumer>();
        // resolved.Dependency is an instance of MyDependency
    }
}

internal class Consumer
{
    [Dependency]
    public IDependency Dependency { get; set; }
}

public interface IDependency
{
}

internal class MyDependency : IDependency
{
}

Unity InjectionProperty不起作用

1 个答案: