Question

好奇为什么。

 public function get_number() {

    if(Model::get()->isEmpty()) {

        $number = Model::create(['number' => '1111111111']);

        $nubmer = $number->number; //(returns a... model, that's a suprise for me)

    } else {

        $number = Model::orderBy('number', 'desc')->first()->number;

        $number = Model::create(['number' => $number+1]);

        $number = $number->number; //(returns a property 1111111112 etc).

    }

return $number;

在这两种情况下，我都试图获得模型的属性：

$number = $number->number;

但是当“If”部分有效时，它返回一个模型（不是属性）...... 当“else”部分工作时，它返回一个属性（我所期望的）。

这意味着我对Laravel中的某些内容并不了解：）

为什么它会在“If”情况下返回一个完整的模型？:)

Answer 1

您的if阻止包含拼写错误：

public function get_number() {

if(Model::get()->isEmpty()) {

    $number = Model::create(['number' => '1111111111']);

    // this should be $number
    // $nubmer = $number->number;
    // change it to
    $number = $number->number;

} else {

    $number = Model::orderBy('number', 'desc')->first()->number;

    $number = Model::create(['number' => $number+1]);

    $number = $number->number; //(returns a property 1111111112 etc).

}

您也不需要分配$number = $number->number;，只需返回：

return $number->number;

示例：

public function get_number() {
    if(Model::get()->isEmpty()) {
        $number = Model::create(['number' => '1111111111']);
    } else {
        $number = Model::orderBy('number', 'desc')->first()->number;
        $number = Model::create(['number' => $number+1]);
    }

    return $number->number;
}

Laravel模型奇怪的行为

1 个答案: