Question

这段代码给我一个seg错误

image_t* removeNoiseAverage(image_t* img[]) {

    image_t* average = (image_t*) malloc(sizeof(image_t));

    int image_size = img[0]->header.HEIGHT * img[0]->header.WIDTH;
    int i,k;
    double avg = 0;
    for (i=0;i<image_size;i++){
        avg = 0;
        for (k=0;k<10;k++){
            avg += img[k]->pixels[i].R;
        }
        avg = avg/10;
        average->pixels[i].R = avg;
    }

    return 0;
}

typedef struct image {
  header_t header;      // 15 bytes
  pixel_t* pixels;      // 4 bytes
} image_t;

typedef struct pixel {
  uint8_t R, G, B;
} pixel_t;

typedef struct header {
  char MAGIC_NUMBER[3];
  unsigned int HEIGHT, WIDTH, MAX_COLOR;
} header_t;

image_t是我制作的结构，分段错误发生在average->pixels[i].R = avg;

我的malloc不正确吗？

编辑：已更新以添加声明

Answer 1

image_t* average = (image_t*) malloc(sizeof(image_t));

这会为average分配空间，但不为average->pixels内部空间分配空间。两个指针意味着你需要两个分配。

average->pixels = malloc(image_size * sizeof(pixel_t));

我的代码中的分段错误

1 个答案: