java.sql.SQLException:列索引输出范围,(int)< 1

时间:2018-02-22 05:26:52

标签: java mysql jdbc auto-generate

我似乎无法找到获取自动生成密钥的正确代码。 以下是我的代码:

private void btnLogActionPerformed(java.awt.event.ActionEvent evt) {
Calendar cal = Calendar.getInstance();
        cal.getTime();
        SimpleDateFormat sdf1 = new SimpleDateFormat("yyyy/MM/dd");
        SimpleDateFormat sdf2 = new SimpleDateFormat("yyyy/MM/dd hh:mm:ss");

String sql ="select * from tblaccount where Username=? and Password=?";

这是登录帐户

try{

            pst=(PreparedStatement) conn.prepareStatement(sql);
            pst.setString(1,txtUser.getText());
            pst.setString(2,txtPass.getText());

            rs=pst.executeQuery();

登录后让字符串在另一个窗口显示。

         if (rs.next()){


              int id = rs.getInt("UserID");
                    PersonnelAccount.UserID = id;
               String username = rs.getString("Username");
                    PersonnelAccount.Username = username; 
               String name = rs.getString("Name");
                    PersonnelAccount.Name = name;

记录用户进入数据库的时间

String sql1 = "Insert into tbltime (Username,date,TimeIn,TimeOut) values(?,?,?,?)"; 

 ("Insert into tbltime (Username,date,TimeIn,TimeOut) values (?,?,?,?)");

                pst1=(PreparedStatement)conn1.prepareStatement(sql1,Statement.RETURN_GENERATED_KEYS) ;
                pst1.setString(1,txtUser.getText());
                pst1.setString(2,sdf1.format(cal.getTime()));
                pst1.setString(3,sdf2.format(cal.getTime()));
                pst1.setString(4,"0000/00/00 00:00:00");

                pst1.executeUpdate();
                rs1=pst1.getGeneratedKeys();

             if(rs1.next()){

我想我在这里得到了错误...我想获取自动生成密钥,以便我可以更新Timeout数据库。所以我想获得TimeID

                 String time = rs1.getString(+rs1.getInt(1));
                  PersonnelAccount.TimeID = time;



              setVisible(false);
              P_Loading ob=new P_Loading();
              ob.setUpLoading();
              ob.setVisible(true);
              }
       }



            else{
                JOptionPane.showMessageDialog(null,"Incorrect Username and/ Password");

             txtUser.setText("");
             txtPass.setText("");
            }
        } catch(Exception e){
            JOptionPane.showMessageDialog(null,e);

        }
       finally {
            try{
                rs1.close();
               pst1.close();
                 rs.close();
               pst.close();


            } catch(Exception e){

0 个答案:

没有答案
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