Laravel 5.6路线

Question

This is the mean problem
I have controllers structures like this 

And i am using this syntax to make routes which is worked good for me

And i calling url in this way

  

{{route（'admin.categories.show'，[$ category-＆gt; id]）}}

i got this error 

Any Solution ?? thanks in advance guys

Answer 1

对路线进行分组时，可以通过添加标记as：

来命名它们

Route::group(['prefix' => 'admin', 'as' => 'admin.'], function (){
    Route::resource('categories', 'Admin/CategoryController');
});

现在应该可以访问route('admin.categories.show')。

Answer 2

解决方案是

  

{{route（'categories.show'，[$ category-＆gt; id]）}}

跳过管理员感谢每一个人。