Question

我有以下表结构

表hour_rate

CREATE TABLE `hour_rate` (
 `hour_rate_id` int(11) NOT NULL AUTO_INCREMENT,
 `hour_rate` decimal(8,2) NOT NULL,
 `from_date` date NOT NULL,
 `employee_id` int(11) NOT NULL,
 PRIMARY KEY (`hour_rate_id`),
 UNIQUE KEY `idx-unique-hour_rate-from_date-employee_id`
     (`from_date`,`employee_id`),
 KEY `idx-hour_rate-employee_id` (`employee_id`),
 CONSTRAINT `fk-hour_rate-employee_id` FOREIGN KEY (`employee_id`) 
     REFERENCES `employee` (`employee_id`) ON DELETE CASCADE ON UPDATE CASCADE,
) ENGINE=InnoDB;

表employee_work

CREATE TABLE `employee_work` (
 `employee_work_id` int(11) NOT NULL AUTO_INCREMENT,
 `project_id` int(11) NOT NULL,
 `employee_id` int(11) NOT NULL,
 `date` date NOT NULL,
 `hours` int(11) NOT NULL,
 PRIMARY KEY (`employee_work_id`),
 UNIQUE KEY `idx-unique-employee_work-employee_id-date` 
     (`employee_id`,`date`),
 KEY `idx-employee_work-employee_id` (`employee_id`),
 CONSTRAINT `fk-employee_work-employee_id` FOREIGN KEY (`employee_id`) 
     REFERENCES `employee` (`employee_id`) ON DELETE CASCADE ON UPDATE CASCADE,
) ENGINE=InnoDB;

表hour_rate包含有关员工及其小时费率（hour_rate）的记录，从日期开始（from_date）

表employee_work包含员工每天工作时间的记录

我想根据employee_work和hour_rate从date选择具有适当小时费率的所有记录from_date，以便我可以计算员工的付款（{{ 1}} * hour_rate）

例如，我有以下记录在hours

hour_rate

并在+-----------+------------+-------------+ | hour_rate | from_date | employee_id | +-----------+------------+-------------+ | 11.00 | 2018-01-10 | 1 | | 12.00 | 2018-01-14 | 1 | | 13.00 | 2018-01-18 | 1 | | 5.00 | 2018-01-01 | 1 | | 10.00 | 2018-01-15 | 2 | +-----------+------------+-------------+

employee_work

我希望产生以下结果

+-------------+------------+-------+
| employee_id | date       | hours |
+-------------+------------+-------+
|           1 | 2018-01-01 |     8 |
|           1 | 2018-01-02 |     8 |
|           1 | 2018-01-03 |     8 |
|           1 | 2018-01-04 |     8 |
|           1 | 2018-01-05 |     8 |
|           1 | 2018-01-08 |     8 |
|           1 | 2018-01-09 |     8 |
|           1 | 2018-01-10 |     8 |
|           1 | 2018-01-11 |     8 |
|           1 | 2018-01-12 |     8 |
|           1 | 2018-01-15 |     8 |
|           1 | 2018-01-16 |     8 |
|           1 | 2018-01-17 |     8 |
|           1 | 2018-01-18 |     8 |
|           1 | 2018-01-19 |     8 |
+-------------+------------+-------+

Answer 1

一种方法使用相关子查询来获取速率：

select ew.*,
       (ew.hours *
        (select hr.hour_rate
         from hour_rate hr
         where hr.employee_id = ew.employee_id and
               hr.from_date >= ew.date
         order by hr.from_date
         limit 1
        )
       ) as daily_pay
from employee_work ew;

Answer 2

您可以使用带2个表的select来完成此操作。您的数据示例如下：

select ew.employee_id, ew.date, ew.hours, hr.employee_id, hr.from_date (hr.hour_rate * ew.hours) as payment

from employee_work ew, hour_rate hr 

where ew.employee_id = hr.employee_id

mysql - 根据开始日期和日期加入两个表

2 个答案: