Question

public class A6{
    public static void main(String[] args){
        String personInfo[][]={ 
                {"Anderson",  "Varejao",     "1125"},
                {"Giorgi",  "Tevzadze",      "1125"},
                {"Will",      "Cherry",      "1225"},
                {"Kevin",     "Love",        "2525"},
                {"Kyrie",     "Livings",      "454"},
                {"Dion",      "Malborg",    "6250" } 
        };

        //max - who has the highest salary
        if(args[0].equals("max")){
            int max = Integer.parseInt(personInfo[0][2]);

            for(int i = 0; i < personInfo.length; i++) {
                int l = Integer.parseInt(personInfo[i][2]);        
                if(max < l){
                    max = l;
                }
             }

            for(int i = 0; i < personInfo.length; i++) {
                if(max == Integer.parseInt(personInfo[i][2])){
                     System.out.println(personInfo[i][0]);
                }
            }
            System.out.println("His sallary is:" +max );


        //  va ZZZ        - who has the closest salary to value ZZ
        if(args[0].equals("va")){
            for(int iž0; i < personInfo.length; i++{

            int l = Integer.parseInt(personInfo[i][2]);
            ...

        }
    }
}

我已经写了一个找到工资最高的人的方法，现在我正在努力找到与我输入的值最接近的工资。例如：我进入命令行java A6 456，应该从命令行Kyrie Livings得到答案。我已经开始通过编写for循环并将字符串值从personInfo转换为int来完成此操作。有什么建议吗？

Answer 1

试试这个:(考虑到内存使用没有限制）：

int index = 0, minDiff = 0, diff = 0;

for(int i = 0;i<personInfo.length;i++){
    diff = Math.abs(personInfo[i][2] - inputVal);
    if(diff<minDiff){
        minDiff = diff;
        index = i;
    }        

}
return personInfo[index][2];

inputVal是您要传递给此函数的参数，您要为其找到最近的工资。您可以修改此逻辑以满足此用例的需求。

如何从数组中找到最近的值？

1 个答案: