我尝试使用CreateAdaptiveComponentInstance创建一个族实例，并尝试将其托管在一个参考点上，该参考点也是CurveByPoints（样条曲线）的控制点。 系列正确连接到参考点，但参考点工作平面的旋转完全被忽略。
试试这个独立的例子。移动参考点P2 - ＆gt; P1的横截面不会旋转。 现在，重建并更改＆gt;＆gt; if（true）＆lt;＆lt; '假'。现在你看到了我想要的东西。但是一旦你移动点P2，P2的坐标和家族之间的链接就会被打破。
CurveByPoints spl = null;
ReferencePointArray pts = null;
// create ref points
var p1 = doc.FamilyCreate.NewReferencePoint(new XYZ( 0, 0, 0)); p1.Name = "P1";
var p2 = doc.FamilyCreate.NewReferencePoint(new XYZ(10,10, 0)); p2.Name = "P2";
var p3 = doc.FamilyCreate.NewReferencePoint(new XYZ(30,20, 0)); p3.Name = "P3";
pts = new ReferencePointArray();
pts.Append(p1); pts.Append(p2); pts.Append(p3);
// create a spline
spl = doc.FamilyCreate.NewCurveByPoints(pts);
spl.Visible = true;
spl.IsReferenceLine = false; // MOdelliinie
// change points to adaptive points
foreach(ReferencePoint p in pts)
{
AdaptiveComponentFamilyUtils.MakeAdaptivePoint(doc, p.Id, AdaptivePointType.PlacementPoint);
p.CoordinatePlaneVisibility = CoordinatePlaneVisibility.Always;
p.ShowNormalReferencePlaneOnly = true;
}
// find an adaptive family to place at the points
FamilySymbol fam_sym = null;
var filter = new FilteredElementCollector(doc);
ICollection<Element> col = filter.OfClass(typeof(FamilySymbol)).ToElements();
if(col!=null)
{
foreach(FamilySymbol ele in col)
{
if(ele == null || !AdaptiveComponentInstanceUtils.IsAdaptiveFamilySymbol(ele) ) {continue;}
if(fam_sym == null)
{
fam_sym=ele;
}
if(ele.Name == "profil_adapt_offset_einfach2") // use a special one instead of the first matching
{
fam_sym = ele as FamilySymbol;
break;
}
}
}
// create family instances
if(fam_sym != null)
{
if(true) // this is waht I want. Try "false" to see what I expect
{
foreach (ReferencePoint p in pts)
{
var inst = AdaptiveComponentInstanceUtils.CreateAdaptiveComponentInstance(doc, fam_sym);
var placements = AdaptiveComponentInstanceUtils.GetInstancePlacementPointElementRefIds(inst);
ReferencePoint fam_pt = doc.GetElement(placements.FirstOrDefault()) as ReferencePoint;
var pl = Plane.CreateByNormalAndOrigin(new XYZ(1,0,0), p.Position);
// #### I THINK HERE IS MY PROBLEM ####
// "plane" just points to the reference POINT,
// and not the XZ-PLANE of the reference point.
Reference plane = p.GetCoordinatePlaneReferenceYZ();
PointOnPlane pop = doc.Application.Create.NewPointOnPlane(plane, UV.Zero, UV.BasisU, 0.0);
fam_pt.SetPointElementReference(pop);
}
}
else
{
// create family instances and place along the path
// -> looks good until you move a reference point
double ltot=0.0;
for(var i=0; i<pts.Size-1; ++i)
{
ltot += pts.get_Item(i).Position.DistanceTo(pts.get_Item(i+1).Position);
}
double lfromstart=0;
for(var i=0; i<pts.Size; ++i)
{
if(i>0)
{
lfromstart += pts.get_Item(i).Position.DistanceTo(pts.get_Item(i-1).Position);
}
var inst = AdaptiveComponentInstanceUtils.CreateAdaptiveComponentInstance(doc, fam_sym);
var placements = AdaptiveComponentInstanceUtils.GetInstancePlacementPointElementRefIds(inst);
var location = new PointLocationOnCurve(PointOnCurveMeasurementType.NormalizedCurveParameter, lfromstart / ltot, PointOnCurveMeasureFrom.Beginning);
PointOnEdge po = doc.Application.Create.NewPointOnEdge(spl.GeometryCurve.Reference, location);
// attach first adaptive point to ref point
var firstPoint = doc.GetElement(placements.FirstOrDefault()) as ReferencePoint;
firstPoint.SetPointElementReference(po);
}
}
}
我在这里使用Revit 2018.2。
人们也可能会搜索：GetCoordinatePlaneReferenceXZ，GetCoordinatePlaneReferenceXY。
[edit1]
[edi2] - 我发现，例如手动更改ReferencePoint.CoordinatePlaneVisibility = true将创建我需要的SketchPlane。但我不能在代码中这样做：
var sel = new List<ElementId>();
foreach (ReferencePoint p in pts)
{
sel.Add(p.Id);
// make plane visible
p.CoordinatePlaneVisibility = CoordinatePlaneVisibility.Always;
// shake point
ElementTransformUtils.MoveElement(doc, p.Id, XYZ.BasisX);
ElementTransformUtils.MoveElement(doc, p.Id, XYZ.BasisX.Negate());
}
ui_doc.Selection.SetElementIds(sel);
doc.Regenerate();
ui_doc.RefreshActiveView();
答案 0 :(得分：0)
如果您使用import React, { Component } from 'react';
import Select from 'react-select';
import 'react-select/dist/react-select.css';
import Api from '../../Api'
import DatePicker from 'material-ui/DatePicker';
import RaisedButton from 'material-ui/RaisedButton';
import { Recharts } from 'recharts';
const { LineChart, Line, XAxis, YAxis, CartesianGrid, Tooltip, Legend } = Recharts;
const data = [
{ name: 'Page A', uv: 4000, pv: 2400, amt: 2400 },
{ name: 'Page B', uv: 3000, pv: 1398, amt: 2210 },
{ name: 'Page C', uv: 2000, pv: 9800, amt: 2290 },
{ name: 'Page D', uv: 2780, pv: 3908, amt: 2000 },
{ name: 'Page E', uv: 1890, pv: 4800, amt: 2181 },
{ name: 'Page F', uv: 2390, pv: 3800, amt: 2500 },
{ name: 'Page G', uv: 3490, pv: 4300, amt: 2100 },
];
render() {
return (
<div className="container">
<LineChart width={600} height={300} data={this.data}
margin={{top: 5, right: 30, left: 20, bottom: 5}}>
<XAxis dataKey="name"/>
<YAxis yAxisId="left" />
<YAxis yAxisId="right" orientation="right" />
<CartesianGrid strokeDasharray="3 3"/>
<Tooltip/>
<Legend />
<Line yAxisId="left" type="monotone" dataKey="pv" stroke="#8884d8" activeDot={{r: 8}}/>
<Line yAxisId="right" type="monotone" dataKey="uv" stroke="#82ca9d" />
</LineChart>
</div>
);
}
}
重载使用NewReferencePoint参数，请参阅NewReferencePoint Method (Transform)？这可能会为您定义所需的平面并将其与该点相关联。
答案 1 :(得分：0)
开发团队回复了附件ZIP文件中提供的详细说明和测试项目：
开发人员似乎需要一些我们尚未公开的API。 PointElement的API是在RIDL之前编写的，因此整个用户界面不会暴露给API。他们需要一个API来获得与其正在驱动的曲线垂直的参考平面。这个平面与API PointElement.GetCoordinatePlaneReferenceYZ()（暴露给API的三个平面之一）所暴露的平面不同。
根据SketchPlanes没有创建（在链接的zip文件中看到的宏），是的，这是正确的并且与UI匹配。 SketchPlanes是元素，与Autodesk.Revit.DB.Reference不同。在我们必须之前，我们不会创建它们。他们也收集了垃圾。在描述的最后，我看到一些应该工作的代码（假设它们将它包装在事务中）。通常，仅选择点将触发从UI创建SketchPlane。除此之外，我仍然不建议将SketchPlane用于他们想要做的事情。
虽然他们想要的东西在API中不存在，但它仍然并不意味着他们想要实现的目标没有解决方法。如果Selection或Reference API公开元素Autodesk.Revit.DB.Reference上的可选/可见引用，则可以迭代这些引用并托管该点。这是通用的Element / Reference API。
我希望这可以澄清。