Question

我有一个场地模型，每个场地属于一个区域和一个类型。我在索引页面上有两个由复选框组成的表单，允许我过滤它们所属的类型或区域所显示的场地记录。但是，只使用了def索引中的最后一行，我如何组合它们才能使两个表单都处于活动状态？

控制器：

class VenuesController < ApplicationController

  def index
    @venues = Venue.all(:conditions => {:area_id => params[:areas]})
    @venues = Venue.all(:conditions => {:venuetype_id => params[:venuetypes]})
  end
end

查看：

<div class="filter_options_container">

  <form class="filter_by_area_form", method="get">
    <% Area.all.each do |a| %>
      <%= check_box_tag("areas[]", a.id) %>
      <%= a.name %>
    <% end %>
    <input type="submit" value="Filter" />
  </form>

  <br><br>

  <form class="filter_by_venuetype_form", method="get">
    <% Venuetype.all.each do |v| %>
      <%= check_box_tag("venuetypes[]", v.id) %>
      <%= v.name %>
    <% end %>
    <input type="submit" value="Filter" />
  </form>
</div>

<div class="venue_partials_container">
  <%= render :partial => 'venue', :collection => @venues %>
  <div class="clearall"></div>
  <%= link_to 'add a new venue', new_venue_path, :class => "add_new_venue_button" %>
</div>

因此，只有venuetype表单有效，或者如果我将def索引更改为：

  def index
    @venues = Venue.all(:conditions => {:venuetype_id => params[:venuetypes]})
    @venues = Venue.all(:conditions => {:area_id => params[:areas]})
  end

然后只有区域才有效。

修改

我已将控制器更改为：

  def index
    @venues = Venue.all(:conditions => {:venuetype_id => params[:venuetypes]}&&{:area_id => params[:areas]})
  end

和观点：

<div class="filter_options_container">
  <form class="filter_form", method="get">
    <fieldset class="filter_form_fieldset">
      <% Area.all.each do |a| %>
        <%= check_box_tag("areas[]", a.id) %>
        <%= a.name %>
      <% end %>
    </fieldset><br>

    <fieldset class="filter_form_fieldset">
      <% Venuetype.all.each do |v| %>
        <%= check_box_tag("venuetypes[]", v.id) %>
        <%= v.name %>
      <% end %>
      <input type="submit" value="Filter" />
    </fieldset>
  </form>
</div>

从表单中选择区域和类型并单击提交按钮后，URL显示“/ venues？areas [] = 2＆amp; venuetypes [] = 13”，但仍然只按区域过滤结果而不是类型。

感谢您的帮助。

Answer 1

要构建搜索查询，您可以使用scoped：

Rails 2

@venues = Venue.scoped
@venues = @venues.scoped(:conditions => { :venuetype_id => params[:venuetypes] }) if params[:venuetypes].present?
@venues = @venues.scoped(:conditions => { :area_id => params[:areas] }) if params[:areas].present?

如果您创建了像@Steve Smith建议的命名范围：

class Venue < ActiveRecord::Base
  named_scope :with_type, lambda { |types|
    types.present? ? { :conditions => { :venuetype_id => types } } : {} }
  named_scope :with_area, lambda { |areas|
    areas.present? ? { :conditions => { :area_id => areas } } : {} }
end

然后你就可以做到：

@venues = Venue.with_type(params[:venuetypes]).with_area(params[:areas])

Rails 3

@venues = Venue.scoped
@venues = @venues.where(:venuetype_id => params[:venuetypes]) if params[:venuetypes].present?
@venues = @venues.where(:area_id => params[:areas]) if params[:areas].present?

或者：

class Venue < ActiveRecord::Base
  scope :with_type, lambda { |types|
    types.present? ? where(:venuetype_id => types) : scoped }
  scope :with_area, lambda { |areas|
    areas.present? ? where(:area_id => areas) : scoped }
end

然后你就可以做到：

@venues = Venue.with_type(params[:venuetypes]).with_area(params[:areas])

我怎样才能进行多次搜索？

1 个答案: