如何在clob列中更新Html

时间:2018-03-01 07:28:00

标签: plsql oracle11g

我无法更新clob列中的html内容:

DECLARE
   LONGLITERAL RAW(32767) := UTL_RAW.CAST_TO_RAW(
        '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml">
          <head>
          <meta http-equiv="Content-Type" content="text/html; charset=utf-8">
            <title>Promotional email template</title>
          </head>
            <body bgcolor="#eeeeee">
              <!-- Start Header -->
             </body>
          </html>');
BEGIN
  EXECUTE IMMEDIATE
  UPDATE table_name SET gno_clob = :1 WHERE id = 'column_id' USING LONGLITERAL;
END;

我也试过

EXECUTE IMMEDIATE
  UPDATE table_name SET gno_clob = LONGLITERAL WHERE id = 'column_id';
END;        

错误

    PLS-00103: Encountered the symbol "END" 
    06550. 00000 -  "line %s, column %s:\n%s"
    *Cause:    Usually a PL/SQL compilation error   
  • 任何建议都是最受欢迎的。

1 个答案:

答案 0 :(得分:0)

请尝试以下方法:

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">

<script src="https://code.jquery.com/jquery-3.2.1.slim.min.js" integrity="sha384-KJ3o2DKtIkvYIK3UENzmM7KCkRr/rE9/Qpg6aAZGJwFDMVNA/GpGFF93hXpG5KkN" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.9/umd/popper.min.js" integrity="sha384-ApNbgh9B+Y1QKtv3Rn7W3mgPxhU9K/ScQsAP7hUibX39j7fakFPskvXusvfa0b4Q" crossorigin="anonymous"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js" integrity="sha384-JZR6Spejh4U02d8jOt6vLEHfe/JQGiRRSQQxSfFWpi1MquVdAyjUar5+76PVCmYl" crossorigin="anonymous"></script>

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