表中的随机数

Question

我正在尝试制作2个表，其中一个将存储数字，第二个将显示此数字两次，用户也决定将生成多少个数字。

Example:
Table1 -> 67 9 4 -78 -29
Table2 -> 67 67 9 9 4 4 -78 -78 -29 -29

当前代码：

#region TablesTest

    Console.Write("Enter n: ");
    int n = Convert.ToInt32(Console.ReadLine());

    int[] table1 = new int[n];
    int[] table2 = new int[n];

    Random rnd = new Random();

    for (int i = 0; i < n; i++)
    {
        table1[i] = rnd.Next(-100, 100);

        foreach (int x in table1)
        {

            table2[i] = table1[i] + table1[i];
            Console.Write(table2[i]);
        }

    }

    Console.ReadKey();
#endregion

Answer 1

如果我理解你的问题，这应该有效：

Console.Write("Enter n: ");
int n;
if (Int32.TryParse(Console.ReadLine(), out n))
{
    int[] table1 = new int[n];

    Random rnd = new Random();

    //put n randon numbers into table1
    Console.Write("Table1 -> ");
    for (int i = 0; i<n; i++)
    {
        table1[i] = rnd.Next(-100, 100);
        Console.Write(table1[i] + " ");
    }

    Console.WriteLine();

    //foreach number in table1, add two to table2
    int[] table2 = new int[n * 2];
    Console.Write("Table2 -> ");
    for (int i = 0; i<n; ++i)
    {
        table2[i] = table1[i];
        table2[i + 1] = table1[i];

        Console.Write(table2[i] + " ");
        Console.Write(table2[i + 1] + " ");
    }
    Console.ReadKey();
}

它将n个随机数放入table1，然后将相同的数字加到table2两次。