Question

我有两个对象说firstObject和secondObject。现在我必须对firstObject进行排序，使其值与secondObject匹配。这是对象

firstObject

     0:{id: 23, code: "SONGS", value: "Songs"}
     1:{id: 24, code: "ATHELETE", value: "Athelete"}
     2:{id: 25, code: "DANCE", value: "Dance"}
     3:{id: 28, code: "MUSIC_BASE", value: "Music base"}
     4:{id: 31, code: "SPORTS", value: "Sports"}

secondObjects

   {"Sports":2,"Dance":3,"Music base":4,"Athelete":3,"Songs":1}

排序后firstObject应该有订单Sports ,Dance ,Music base ,Athelete ,Songs

Answer 1

你需要有一个比较Object.keys(secondObj).indexOf(a.value) - Object.keys(secondObj).indexOf(b.value)的功能。因为你需要根据当前元素的值来比较secondObj中键的值索引。

var firstObj = [{id: 23, code: "SONGS", value: "Songs"},
{id: 24, code: "ATHELETE", value: "Athelete"},
{id: 25, code: "DANCE", value: "Dance"},
{id: 28, code: "MUSIC_BASE", value: "Music base"},
{id: 31, code: "SPORTS", value: "Sports"}]

var secondObj = {"Sports":2,"Dance":3,"Music base":4,"Athelete":3,"Songs":1};

var sorted = firstObj.sort(
  (a,b) => Object.keys(secondObj).indexOf(a.value) - Object.keys(secondObj).indexOf(b.value)
);

console.log(sorted);

Answer 2

正如我在对原始问题的评论中所说的那样，对象密钥不能保证订购，所以你的问题本质上是有缺陷的。

但是如果我们想要假设你总是在对象键保持有序的引擎中运行，你可以这样做：

let firstObj = [{id: 23, code: "SONGS", value: "Songs"},
    {id: 24, code: "ATHELETE", value: "Athelete"},
    {id: 25, code: "DANCE", value: "Dance"},
    {id: 28, code: "MUSIC_BASE", value: "Music base"},
    {id: 31, code: "SPORTS", value: "Sports"}];

let secondObj = {"Sports":2,"Dance":3,"Music base":4,"Athelete":3,"Songs":1};

let newArray = [];
Object.keys(secondObj).forEach(key => {
    newArray.push(firstObj.find(o => o.value === key));
});

newArray将firstObj与secondObj中的键具有相同的顺序

如何根据其他对象对Object进行排序

2 个答案: