Question

我有一个像这样的DataFrame df：

Pattern    String                                       
101        hi, how are you?
104        what are you doing?
108        Python is good to learn.

我想为String Column创建ngrams。我使用split()和stack()

创建了unigram

new= df.String.str.split(expand=True).stack()

但是，我想创建ngrams（bi，tri，quad等）

Answer 1

对文本列进行一些预处理，然后进行一些转换+连接：

# generate unigrams 
i = df.String\
      .str.lower()\
      .str.replace('[^a-z\s]', '')\
      .str.split(expand=True)\
      .stack()

# generate bigrams by concatenating unigram columns
j = i + ' ' + i.shift(-1)
# generate trigrams by concatenating unigram and bigram columns
k = j + ' ' + i.shift(-2)

# concatenate all series vertically, and remove NaNs
pd.concat([i, j, k]).dropna().reset_index(drop=True)

0                   hi
1                  how
2                  are
3                  you
4                 what
5                  are
6                  you
7                doing
8               python
9                   is
10                good
11                  to
12               learn
13              hi how
14             how are
15             are you
16            you what
17            what are
18             are you
19           you doing
20        doing python
21           python is
22             is good
23             good to
24            to learn
25          hi how are
26         how are you
27        are you what
28        you what are
29        what are you
30       are you doing
31    you doing python
32     doing python is
33      python is good
34          is good to
35       good to learn
dtype: object

Answer 2

everygrams()函数返回连续n次序的ngram，例如：以下返回1至3克：

>>> from nltk import everygrams
>>> everygrams('a b c d'.split(), 1, 3)
<generator object everygrams at 0x1147e3410>
>>> list(everygrams('a b c d'.split(), 1, 3))
[('a',), ('b',), ('c',), ('d',), ('a', 'b'), ('b', 'c'), ('c', 'd'), ('a', 'b', 'c'), ('b', 'c', 'd')]

使用apply：

>>> import pandas as pd
>>> from itertools import chain
>>> from nltk import everygrams, word_tokenize
>>> df = pd.read_csv('x.tsv', sep='\t')
>>> df
   Pattern                    String
0      101          hi, how are you?
1      104       what are you doing?
2      108  Python is good to learn.

>>> df['String'].apply(lambda x: [' '.join(ng) for ng in everygrams(word_tokenize(x), 1, 3)])
0    [hi, ,, how, are, you, ?, hi ,, , how, how are...
1    [what, are, you, doing, ?, what are, are you, ...
2    [Python, is, good, to, learn, ., Python is, is...
Name: String, dtype: object

>>> list(chain(*list(df['1to3grams'])))
['hi', ',', 'how', 'are', 'you', '?', 'hi ,', ', how', 'how are', 'are you', 'you ?', 'hi , how', ', how are', 'how are you', 'are you ?', 'what', 'are', 'you', 'doing', '?', 'what are', 'are you', 'you doing', 'doing ?', 'what are you', 'are you doing', 'you doing ?', 'Python', 'is', 'good', 'to', 'learn', '.', 'Python is', 'is good', 'good to', 'to learn', 'learn .', 'Python is good', 'is good to', 'good to learn', 'to learn .']

从pandas dataframe列生成ngrams

2 个答案: