仅提取和馈送来自一个表的数据。不从另一个

时间:2018-03-07 16:57:18

标签: php xampp

我无法在语法中找到错误。我得到的结果是数据只从表中获取并送到其他表但不从另一个表中获取。

<?php

include "new.php";

$cgpa = mysqli_real_escape_string($link, $_GET['cgpa']);
$browser = mysqli_real_escape_string($link, $_GET['browser']);

$sql = "SELECT ROLLNO,NAME,DEPARTMENT,CGPA FROM l3 WHERE CGPA >= '$cgpa'";
$sql3 = "SELECT SYSTEMNUMBER FROM l2 WHERE BROWSER= '$browser'";

$result = mysqli_query($link, $sql);
$result1 = mysqli_query($link, $sql3);
if (mysqli_num_rows($result) > 0) {
    while($row = mysqli_fetch_assoc($result)) {
        $sql2 = "INSERT INTO l4 (ROLLNO,NAME,DEPARTMENT,CGPA)VALUES({$row['ROLLNO']},'{$row["NAME"]}','{$row["DEPARTMENT"]}',{$row["CGPA"]})";
        mysqli_query($link, $sql2);
    }
}

else
    echo "No records found.";
  //  mysqli_close($link);

if (mysqli_num_rows($result1) > 0) {
    while($row = mysqli_fetch_assoc($result1)) {
        $sql4 = "UPDATE l4 (SYSTEMNUMBER)VALUES({$row['SYSTEMNUMBER']})";
        mysqli_query($link, $sql4);
    }
}

else
    echo "No records found.";

mysqli_close($link);
?>

0 个答案:

没有答案