Question

如何正确输出此新闻网站上的所有链接？（以列表形式）
以列表形式输出后，如何随机返回结果（一次3~5个链接）

注意：我需要的代码从第739行开始（几乎可能会改变一点，导致它每天刷新）

div class="abdominis rlby clearmen"

我需要这种事情中的每一个环节

<a href="https://tw.news.appledaily.com/life/realtime/20180308/1310910/>

谢谢！代码如下：

from bs4 import BeautifulSoup
from flask import Flask, request, abort
import requests
import re
import random
import types    
target_url = 'http://www.appledaily.com.tw/realtimenews/section/new/'
print('Start parsing appleNews....')
rs = requests.session()
res = rs.get(target_url, verify=False)
soup = BeautifulSoup(res.text, 'html.parser')

#can output all links but with useless information
contents = soup.select("div[class='abdominis rlby clearmen']")[0].find_all('a')
print(contents)

#can output single link but not in list form
#contents = soup.select("div[class='abdominis rlby clearmen']")[0].find('a').get('href')
#print(contents)

Answer 1

这是一个解决方案，如果它包含在指定的div中，它会将每个链接附加到列表中。

from bs4 import BeautifulSoup
from flask import Flask, request, abort
import requests
import re
import random
import types    
target_url = 'http://www.appledaily.com.tw/realtimenews/section/new/'
print('Start parsing appleNews....')
rs = requests.session()
res = rs.get(target_url, verify=False)
soup = BeautifulSoup(res.text, 'html.parser')

list_links = [] # Create empty list

for a in soup.select("div[class='abdominis rlby clearmen']")[0].findAll(href=True): # find links based on div
    list_links.append(a['href']) #append to the list
    print(a['href']) #Check links

for l in list_links: # print list to screen (2nd check)
    print(l)

创建要返回的随机链接。

import random #import random module

random_list = [] #create random list if needed..
random.shuffle(list_links) #random shuffle the list

for i in range(5): # specify range (5 items in this instance)
    try:
        res = list_links.pop(random.randint(0, len(list_links))) # pop of each item randomly based on the size of the list
        print(res) #print to screen..
        random)list.append(res) # or append to random_list
    except IndexError:
        pass

您要求退回的最后一次编辑..

这是一个函数，它返回x个随机链接数量的列表..

def return_random_link(list_, num):
    """ Takes in a list and returns a random amount of items """
    random.shuffle(list_)

    random_list = []

    for i in range(num):
        try: # try to append to the list
            r = list_.pop(random.randint(0, len(list_)))
            random_list.append(r)
        except IndexError: #except an IndexError (no items
            return random_list # Return the list of items

    return random_list

random_list = return_random_link(list_links, 5)

for i in random_list:
    print(i)

Answer 2

如果您想要没有其后代的链接标记，您可以清除它们：

for elm in contents:
    elm.clear()

我想象一下，我对提取链接更感兴趣：

contents = [a['href'] for a in contents]

要以随机顺序获取结果，请尝试使用random.shuffle（）并在需要时从重新排列的列表中获取多个元素。

Beautifulsoup - webcrawler的问题

2 个答案: