获取前一个兄弟的Java XPath表达式

Question

Given the below XML
</parties>
    <party>
        <name>Tom</name>
        <typeCode>D</typeCode>
        <typeDesc>Defendant</typeDesc>
        <info></info>
        <otherData>
           <partySeqNum>2</partySeqNum>
           <partyTitle></partyTitle>
           <partyAddDate></partyAddDate>
           <terminateDate></terminateDate>
           <indexPartyName>Tom</indexPartyName>
        </otherData>
    </party>
    <party>
        <name>Jim</name>
        <typeCode>DE</typeCode>
        <typeDesc>Defendant</typeDesc>
        <info></info>
        <otherData>
           <partySeqNum>2</partySeqNum>
           <partyTitle></partyTitle>
           <partyAddDate></partyAddDate>
           <terminateDate></terminateDate>
           <indexPartyName>Tom</indexPartyName>
        </otherData>
    </party>
</parties>

我有一个util，它返回xpath：/parties/party(1)/typeDesc

有没有办法可以让表达式返回/parties/party(1)/typeDesc之前的兄弟/parties/party(1)/typeCode。

我很一般，无论我得到什么xpath表达式，我都需要得到它以前的兄弟。

xPath.compile(expression).evaluate(xmlDocumentOrg, XPathConstants.NODE);

Answer 1

    String expression = "/parties/party[1]/typeDesc";
    String precedingSiblingExpression = expression + "/preceding-sibling::*[1]";
    Node result = (Node) xpath.compile(precedingSiblingExpression).evaluate(source, XPathConstants.NODE);