Question

我有一个脚本，用于检查db中的重写值并通过结果循环，并使用json回显该值。但是，它只显示1个记录而不是3个正在发送到php的记录。如果有人能指出我的错误，我将不胜感激。感谢

$boxitems = mysqli_real_escape_string($conn, $_POST['box']);
$array = array();
$array = $boxitems;

foreach ($array as $boxes) {

    $sql = "SELECT item FROM act WHERE item = '".$boxes."' GROUP BY item HAVING COUNT(*) > 1";
    $result = mysqli_query($conn, $sql) or die('Error selecting item: ' . mysqli_error());
    $num_rows = mysqli_num_rows($result);
      if($num_rows) {
        while ($row = mysqli_fetch_array($result)) {
              $data[] =  $row['item'];
          }
          echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: red; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
          echo json_encode($data)  . ' already exists. Please enter a unique box reference.';
          echo '</div>';
          exit;
        } else {
          echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: #63c84c; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
          echo 'No dupes found in database.';
          echo '</div>';
          exit;
        }
    }

更新屏幕截图

Answer 1

将您想要回显的内容放入在foreach之外声明的单个变量中并连接每个div（每个div对应一个foreach执行的操作）。然后在循环之后回复它。

$boxitems = $_POST['box'];
$insertedItems = array();
$duplicateItems = array();

foreach ($boxitems as $boxes) {

    $escapedBoxes = mysqli_real_escape_string($conn, $boxes);   
    $sql = "SELECT item FROM act WHERE item = '".$escapedBoxes."' GROUP BY item HAVING COUNT(*) > 0";
    $result = mysqli_query($conn, $sql) or die('Error selecting item: ' . mysqli_error());
    $num_rows = mysqli_num_rows($result);
    if($num_rows) {
        while ($row = mysqli_fetch_array($result)) {
            $duplicateItems[] = $row['item'];
        }            
    }
    else
    {
        $insertedItems[] = $escapedBoxes;
    }
}   

if(!empty($duplicateItems)) {
    echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: red; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
    echo json_encode($duplicateItems)  . ' already exists. Please enter a unique box reference.';
    echo '</div>';
} else {
    echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: #63c84c; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
    echo 'No dupes found in database.<br/>';
    echo json_encode($insertedItems) . ' has been entered successfully into the database.';
    echo '</div>';
}

编辑：考虑了u_mulder评论更新了代码。

Answer 2

$boxitems = mysqli_real_escape_string($conn, $_POST['box']);
$array = array();
$array = $boxitems;

foreach ($array as $boxes) {

    $sql = "SELECT item FROM act WHERE item = '".$boxes."' GROUP BY item HAVING COUNT(*) > 1";
    $result = mysqli_query($conn, $sql) or die('Error selecting item: ' . mysqli_error());
    $num_rows = mysqli_num_rows($result);
      if($num_rows) {
        while ($row = mysqli_fetch_array($result)) {
              $data[] =  $row['item'];
          }
          echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: red; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
          echo json_encode($data)  . ' already exists. Please enter a unique box reference.';
          echo '</div>';
          exit;
        } else {
          echo '<div style="width: 50%; margin-bottom: 20px; border-radius: 5px; border: 1px solid black; background: #63c84c; font-size: 16px; color: white; height: 50px; padding: 15px; line-height: 1.3;">';
          echo 'No dupes found in database.';
          echo '</div>';
        }
     exit;
    }

任何函数，循环或条件内的退出都会使程序退出并继续，因此它不会迭代，它会在第一次迭代后退出。

while循环只显示1个结果

2 个答案: