Question

返回的结果包括结果代码是否已完成两次，即1个数据记录，但PZ01在同一记录上使用两次。我只想算一次。每条记录都有一个唯一的ID，我不想在此报告中显示。所以我希望这个运行给我总和，但是来自独特的记录ID，因此它不会被计算多次。

    select
    sum(case when result_code = 'PZ01' then 1 else 0 end) as Hub_Box_Activated
    ,sum(case when result_code = 'NOTI' then 1 else 0 end) as Not_Interested
    ,sum(case when result_code = 'PZ02' then 1 else 0 end) as No_Tablet_Installed
    ,sum(case when result_code = 'PZ03' then 1 else 0 end) as Customer_Query
    ,sum(case when result_code = 'PZ26' then 1 else 0 end) as NI_Security_Concerns
    ,sum(case when result_code = 'PZ27' then 1 else 0 end) as NI_Storage_Concerns
    ,sum(case when result_code = 'PZ28' then 1 else 0 end) as NI_Using_alternative_provider
    ,sum(case when result_code = 'PZ29' then 1 else 0 end) as NI_Too_Much_Hassle
from
    history
where
    list_id in ('1432','1604','1607')

Answer 1

使用count尝试distinct。只需使用列名

更改查询中的record_id即可

select
    count(distinct case when result_code = 'PZ01' then record_id end) as Hub_Box_Activated
    ,count(distinct case when result_code = 'NOTI' then record_id end) as Not_Interested
    ,count(distinct case when result_code = 'PZ02' then record_id end) as No_Tablet_Installed
    ,count(distinct case when result_code = 'PZ03' then record_id end) as Customer_Query
    ,count(distinct case when result_code = 'PZ26' then record_id end) as NI_Security_Concerns
    ,count(distinct case when result_code = 'PZ27' then record_id end) as NI_Storage_Concerns
    ,count(distinct case when result_code = 'PZ28' then record_id end) as NI_Using_alternative_provider
    ,count(distinct case when result_code = 'PZ29' then record_id end) as NI_Too_Much_Hassle
from
    history
where
    list_id in ('1432','1604','1607')

Answer 2

尝试在强制1值COUNT语句中使用DISTINCT和CASE。请注意，这只会产生值1或0，因为使用特定值计算不同的result_code将始终返回1（如果存在）或0（如果不存在）。

  select
    COUNT(DISTINCT(case when result_code = 'PZ01' then result_code end)) as Hub_Box_Activated
    ,COUNT(DISTINCT(case when result_code = 'NOTI' then result_code end)) as Not_Interested
    ,COUNT(DISTINCT(case when result_code = 'PZ02' then result_code end)) as No_Tablet_Installed
    ,COUNT(DISTINCT(case when result_code = 'PZ03' then result_code end)) as Customer_Query
    ,COUNT(DISTINCT(case when result_code = 'PZ26' then result_code end)) as NI_Security_Concerns
    ,COUNT(DISTINCT(case when result_code = 'PZ27' then result_code end)) as NI_Storage_Concerns
    ,COUNT(DISTINCT(case when result_code = 'PZ28' then result_code end)) as NI_Using_alternative_provider
    ,COUNT(DISTINCT(case when result_code = 'PZ29' then result_code end)) as NI_Too_Much_Hassle
from
    history
where
    list_id in ('1432','1604','1607')

返回不同值

2 个答案: