Question

我试图找到两个功能的解决方案。函数是涉及四个变量（eta，xi，a，c）的积分。代码首先集成eta，然后是xi，只产生a和c的函数。它对两组不同的数据执行此操作，产生两个未知数a和c的两个方程。这些需要解决，但是，我似乎无法使最后一行工作并得到以下错误消息。

 AttributeError: 'Tuple' object has no attribute 'as_coefficient'

如果这段代码写得不好，请道歉 - 我对此非常陌生，非常感谢任何建议！

from numpy import *
from scipy import *
from sympy import *

class dz_by_dxi:
def __init__(self, xi, a, c, lowlim_arg, uplim_arg, n_arg, lowlim_z,
uplim_z, n_z):
    self.xi = xi
    self.a = a
    self.c = c
    self.lowlim_arg = lowlim_arg
    self.uplim_arg = uplim_arg
    self.n_arg = n_arg
    self.lowlim_z = lowlim_z
    self.uplim_z = uplim_z
    self.n_z = n_z

def __call__(self, eta_prime):
    xi, a, c, lowlim_arg, uplim_arg, n_arg, lowlim_z, uplim_z, n_z = (
    self.xi, self.a, self.c, self.lowlim_arg, self.uplim_arg, self.n_arg,
    self.lowlim_z, self.uplim_z, self.n_z)

    integrand_eta = ((eta_prime/(a**2 + eta_prime**2) + eta_prime/(c**2 +
    eta_prime**2) - 2*eta_prime/(1 + eta_prime**2))*(pi -
    2*atan(eta_prime/xi)))

    integral_eta = Integral(integrand_eta, (eta_prime, lowlim_arg,
    uplim_arg))

    arg_dz = integral_eta.as_sum(n_arg, method = "midpoint")

    dz = (abs(sqrt((xi+a)/(xi-a)))*abs(sqrt((xi+c)/(xi-c)))*
    abs(((xi-1)/(xi+1)))*exp((1/pi)*arg_dz))

    z = Integral(dz, (xi, lowlim_z, uplim_z))

    return z.as_sum(n_z, method = "midpoint")

eta = Symbol('eta')
xi = Symbol('xi')
a = Symbol('a')
c = Symbol('c')

lowlim_arg = 0
uplim_arg = 100
n_arg = 2

lowlim_z = 0
uplim_z = 1
n_z = 2

ans_eqn_1 = 1.5
ans_eqn_2 = 0.5


instance_1 = dz_by_dxi(xi, a, c, lowlim_arg, uplim_arg, n_arg, lowlim_z, uplim_z, n_z)
instance_2 = dz_by_dxi(xi, a, c, lowlim_arg, uplim_arg, n_arg, lowlim_z, a, n_z)

eqn_1 = instance_1(eta) - ans_eqn_1
eqn_2 = instance_2(eta) - ans_eqn_2

solution = solve((eqn_1, eqn_2), (a, c), (0.4, 1.7))

找到符号积分系统的解决方案

0 个答案: