Question

我遇到export class test { private static t:test; private name:string; constructor() { t=this; } public static sample() { return t.name; }问题，每当我搜索蓝牙设备时，它会像往常一样显示可用设备列表，但在第二次点击时，它会生成重复项，因为第一次扫描的结果仍然存在，因此，每当用户点击按钮进行扫描时，如何摆脱第一次扫描结果，并在最终用户点击设备的地址或名称时连接到蓝牙设备。

MainActivity.cs

listviews

Device.cs

public class BTReceiver : BroadcastReceiver
    {

        public override void OnReceive(Context context, Intent intent)
        {
            var application = context.ApplicationContext;
            string action = intent.Action;
            if (action == BluetoothDevice.ActionFound)
            {
                BluetoothDevice device = intent.GetParcelableExtra(BluetoothDevice.ExtraDevice) as BluetoothDevice;
                devices.Add(new Devices(device.Name, device.Address));

                Devices item = list.First(d => d.name == device.Name);

                //if devices does not exist in the list, add it in
                if (item != null)
                {
                    return;
                }


                aadapter = new CustomAdapter(_instance, devices);
                availableList.Adapter = aadapter;
                aadapter.NotifyDataSetChanged();

                Toast toast = Toast.MakeText(Android.App.Application.Context, device.Name, ToastLength.Long);
                toast.Show();
            }
        }
    }

BTDevice.cs 又称我创建的自定义适配器

public class Devices
{
    string _name;
    string _address;

    public string Name { get { return _name; } set { _name = value; } }
    public string Address { get { return _address; } set { _address = value; } }

    public Devices(string name, string address)
    {
        Name = name;
        Address = address;
    }
}

Answer 1

您应该在向其添加新内容之前清除设备。像...这样的东西。

clear(devices)
devices.add(newdevice)

列表视图生成重复数据以及从列表视图单击时如何连接到设备

1 个答案: