Question

我想计算一个月的周数，我想计算周数，无论是奇数还是每周，我怎样才能在TSQL中得到它？谢谢大家！

Answer 1

这将为您提供当月@dt的一周。第二列在表达式上使用CASE语句，以显示“奇数”或“偶数”

declare @dt datetime
set @dt = GETDATE()

select
    WhichWeekOfMonth = datepart(wk, @dt)
                     - datepart(wk,dateadd(m, DATEDIFF(M, 0, @dt), 0)) + 1,
    case when (datepart(wk, @dt)
            - datepart(wk,dateadd(m, DATEDIFF(M, 0, @dt), 0)) + 1) % 2 = 1
         then 'Odd' else 'Even' end

Answer 2

它将为您提供每月的周数

declare @dates datetime
select @dates='2011-03-22'
SELECT datepart(dd,@dates), ceiling (cast(datepart(dd,@dates)as numeric(38,8))/7)

Answer 3

可读性，易于定制和可预测......

DECLARE @dayOfMonth AS INT;
SET @dayOfMonth = DATEPART(DAY, '3/14/2013');
SELECT CASE 
    WHEN @dayOfMonth < 8 THEN 1
    WHEN @dayOfMonth < 15 THEN 2
    WHEN @dayOfMonth < 22 THEN 3
    ELSE 4
END AS weekOfMonth;

Answer 4

试试这个：

SELECT (DATEPART(d, '02/07/2011')/7)%2 AS WeekNo, --Replace your date column in place of '02/07/2011'
       CASE (DATEPART(d, '02/07/2011')/7)%2 
                WHEN 1 THEN 'Odd' 
                ELSE 'Even'
             END AS WeekType

Answer 5

我认为这使得这种方法非常明显：

DECLARE @DayOne DATETIME
DECLARE @ThisDay DATETIME
SET @ThisDay = GETDATE()
SET @DayOne = CAST(CAST(MONTH(@ThisDay) AS VARCHAR) + '/1/' + CAST(YEAR(@ThisDay) AS VARCHAR) AS DATETIME)
SELECT (DATEPART(wk, @ThisDay) - DATEPART(wk, @DayOne) + 1) AS [Week Of Month]

SQL Server 2012有一个CONCAT函数，可用于更轻松地构建DayOne字符串：

DECLARE @DayOne DATETIME
DECLARE @ThisDay DATETIME
SET @ThisDay = GETDATE()
SET @DayOne = CAST(CONCAT(MONTH(@ThisDay), '/1/', YEAR(@ThisDay)) AS DATETIME)
SELECT (DATEPART(wk, @ThisDay) - DATEPART(wk, @DayOne) + 1) AS [Week Of Month]

TSQL计算月份的周数

5 个答案: