在某些情况下，在某些情况下工作的时间在其他情况下失败

Question

我们可以从给定的时段中选择任何时间。如果选择的时间比当前时间少1小时，那么我们必须显示警报。以下是我写的。但它并不完全正确。在某些情况下它可以正常工作

select count(*), 
case when age >= 50 then '50 and older' when age < 50 and age >= 35 then '35 to 49' else 'Under 35' end as AgeCat,
count(*)/sum(count(*)) over (partition by '') as percent 
from mydata group by 2;

Answer 1

使用Date在SimpleDateFormat课程中转换deliveryDateTime。 防爆。

try {
            if (currentDate.equals(DeliveryDate)) {
                String deliveryTime = "1:00 PM";
                SimpleDateFormat simpleDateFormat = new SimpleDateFormat(
                        "hh:mm a", Locale.ENGLISH);

                java.util.Date currentDate = simpleDateFormat.parse(deliveryTime);
                Calendar curDate= Calendar.getInstance();
                curDate.setTime(currentDate);
                Calendar currentDateDelivery= Calendar.getInstance();
                currentDateDelivery.set(Calendar.HOUR_OF_DAY,
                        curDate.get(Calendar.HOUR_OF_DAY));
                currentDateDelivery.set(Calendar.MINUTE,
                        curDate.get(Calendar.MINUTE));

                Calendar threeHoursLaterTime = Calendar.getInstance();
                threeHoursLaterTime.add(Calendar.HOUR_OF_DAY, 3);
                if (currentDateDelivery.getTimeInMillis() < threeHoursLaterTime
                        .getTimeInMillis()) {
                    showToast(
                            "Sorry! Delivery Time is less than 3 hours.Cannot place order");
                }
            }
        } catch (Exception e) {
            e.printStackTrace();
        }