可用状态下拉列表

Question

我试图弄清楚我做错了什么来获取错误信息。我的用户模型有一个status_id字段，它是我的状态表的外键，带有id和name字段。

public function scopeAvailable($query, $current = null)
{
    $options = $this->getAvailableOptions($current)->toArray();

    return $query->whereIn('name', $options);
}

public function getAvailableOptions(string $current = null)
{

    $options = collect(['Active', 'Inactive']);

    switch ($current) {
        case 'Active':
            return $options->merge(['Fired', 'Suspended', 'Retired']);

        case 'Injured':
            return $options->merge(['Fired', 'Retired']);

        case 'Suspended':
            return $options->merge(['Suspended', 'Retired']);
    }

    return $options;
}

public function availableStatuses()
{
    $status = $this->status ? $this->status->name : null;

    return UserStatus::available($status)->get();
}

类型错误：传递给App \ Models \ UserStatus :: getAvailableOptions（）的参数1必须是字符串类型或null，给定对象，在/home/vagrant/projects/app/app/Models/UserStatus.php中调用第45行