提取链接文本并写入文件

时间:2018-03-19 13:25:11

标签: python web-crawler

我的抓取工具只有在链接文本包含给定文本并且我将输出写入html文件时才从页面中提取链接。它的工作,但我想在这些链接旁边添加整个链接文本,像这样 - "初级Java开发人员 - https://www.jobs.cz/junior-developer/"我怎样才能做到这一点?

由于

import requests
from bs4 import BeautifulSoup
import re

def jobs_crawler(max_pages):
    page = 1
    file_name = 'links.html'

    while page < max_pages:
        url = 'https://www.jobs.cz/prace/praha/?field%5B%5D=200900011&field%5B%5D=200900012&field%5B%5D=200900013&page=' + str(page)
        source_code = requests.get(url)
        plain_text = source_code.text
        soup = BeautifulSoup(plain_text)
        page += 1
        file = open(file_name,'w')

        for link in soup.find_all('a', {'class': 'search-list__main-info__title__link'}, text=re.compile('IT', re.IGNORECASE)):
            href = link.get('href') + '\n'
            file.write('<a href="' + href + '">'+ 'LINK TEXT HERE' + '</a>' + '<br />')
            print(href)
        file.close()

    print('Saved to %s' % file_name)

jobs_crawler(5)

2 个答案:

答案 0 :(得分:1)

这应该有所帮助。

file.write('''<a href="{0}">{1}</a><br />'''.format(link.get('href'), link.text ))

答案 1 :(得分:0)

试试这个: -

 href = link.get('href') + '\n'
 txt = link.get_text('href') #will give you text
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