Question

这是它应该模拟2次骰子的代码5次。

import java.util.*;

public class RollDice {

    static double die1;
    static double die2;
    static double sum;

    public static void main (String[] args) {
        String output = "";
        for (int i =0; i<5; i= i+1) {
            die1 = (Math.random()*6)+1;
            die1 = (int) die1;
            die2 = (Math.random()*6)+1;
            die2 = (int)die2;
            System.out.println("die 1 "+ die1+" die 2 "+ die2);

            sum = die1+die2;
            System.out.println("The sum is "+ sum);
            if(i>5) break;
        }

    }

}

我需要计算所有卷的平均值而不是每个卷的平均值，因此输出显示卷的总和和所有卷的平均值。

Answer 1

您可以简化

die1 = (Math.random()*6)+1;
die1 = (int) die1;

要

die1 = (int) ((Math.random() * 6) + 1);

但如果你想要精确的值，你就不需要将它强制转换为整数，那就是截断（除去）你的小数位。

总结所有卷，

int total = 0;
int maxRolls = Integer.MAX_VALUE; //lol
for (int roll = 1; roll <= maxRolls; roll++) {
    // roll your dice
    total += (die1 + die2);
}

平均

double average = (total / maxRolls);

输出

System.out.println("Total: " + total + " Average: " + average + " Rolls: " + maxRolls);

欢迎你，现在做自己的功课

Answer 2

如果平均而言你的意思是所有骰子卷的平均值，你可以将它总结为所有卷并除以10。

static double total = 0;

// in your for loop
total += sum;

// after the loop
System.out.println("Average: "+(total/10));

Answer 3

可能是这样的：

public class RollDice {
    public void main(String[] args) {
        int total;
        for(int i = 1; i < 6; i++) {
            int die1 = roll ();
            int die2 = roll();
            System.out.println("die 1 = " + die1 + " and die2 = " + die2);

            int sum = die1 + die2;
            System.out.println("the sum is " + sum);

            total += sum;
        }
        double avg = total / 5.0d;
        System.out.println("the avg is " + avg);
    }

    public int roll() {
        return Math.floor(Math.random()*6 + 1.0d);
    }
}

需要从循环java中计算平均值

3 个答案: