Question

我正在使用Typescript开发一个带有graphql和express的后端API。我正在使用webpack来管理项目开发和构建过程。

我使用raw-loader从文件中将graphql架构和sql查询作为字符串加载。

目前我正面临一些我不太了解的问题。

webpack.config.js

CONTENT_TYPE

server.ts

const path = require('path');

module.exports = {
  target: 'node',
  entry: {
    server: path.resolve(__dirname, 'server.ts'),
  },
  output: {
    filename: 'server.js',
    path: path.resolve(__dirname, 'dist'),
  },
  devtool: 'source-map',
  module: {
    rules: [
      {
        test: /\.(gql|sql)$/,
        loader: 'raw-loader',
      },
      {
        test: /\.ts$/,
        loader: 'ts-loader',
      },
    ],
  },
  resolve: {
    extensions: ['.ts', '.js'],
  },
  watch: {
    ignored: /node_modues/,
  },
};

错误：

import express from 'express';
import morgan from 'morgan';
import bodyParser from 'body-parser';
import graphqlHTTP from 'express-graphql';

import { affairSchema } from './src/schemas';
import affairRoot from './src/resolvers/affairs';

const app = express();

app.use(morgan('combined'));
app.use(bodyParser.json());

app.use(
  '/graphql',
  graphqlHTTP({
    schema: affairSchema,
    rootValue: affairRoot,
    graphiql: true,
  })
);

const port = process.env.PORT || 4000;
app.listen(port, () => console.log('Server waiting on ', port));

Answer 1

您可以使用webpack-node-externals来阻止捆绑节点模块。这可以消除这些错误，但在运行应用程序时当然也需要function MYMODULE_my_custom_submit_handler($form, &$form_state) { $nid = $form_state['values']['nid']; $node = node_load($nid); // to debug: // var_dump($form_state['values'], $node);die; // check diff $to_publish = false ; if ($node->title != $form_state['values']['title']) $to_publish = true; if ($node->body['und'][0]['value'] != $form_state['values']['body']['und'][0]['value']) $to_publish = true ; // and so on... if ($to_publish) { // force the status to 1. $form_state['values']['status'] = 1; } }。

用webpack设置打字稿

1 个答案: