Question

我目前正在处理聚合查询，并希望将以下查询转换为QueryDSL。基本上它的作用是汇总为给定类别销售的所有产品，并获得带有计数的类别＆gt; X

select
    tcc.catcode, tcc.catcount 
from 
    (select 
        g.code catcode, count(*) catcount
    from dwh_aggregated_order a
        join cat_product_category g on g.id=a.product_category_id
    group by g.code) tcc
where tcc.catcount > 2

Answer 1

我认为查询可以简化为：

<!DOCTYPE html>
<html lang="en">

<head>
  <meta charset="UTF-8">
  <title>Joshua Brown</title>
  <style>
    * {
      padding: 0;
      margin: 0;
    }
    
    .top-menu {
      width: 100%;
      height: 80px;
      background-color: #3f3535;
      text-align: center;
    }
    
    h1 {
      font-size: 42px;
      font-weight: lighter;
      font-family: sans-serif;
      color: #2991d9;
      /*
      padding-left: 100px;
      padding-top: 10px;
      */
    }
    
    li {
      /*display: inline-block;*/
      display: inline-flex;
      justify-content: center;
      float: right;
      color: #FFF;
      text-transform: uppercase;
      border-style: 1px #6f6767 solid;
      flex: auto;
      text-align: center;
      list-style-type: none;
      border-right: 1px #6f6767 solid;
    }
    
    li:first-child {
      border-style: none;
    }
    
    ul {
      display: flex;
      /*margin-bottom: 0;*/
      margin: 0 auto;
    }
    
    .li {
      /*padding-left: 50%*/
    }
  </style>
</head>

<body>
  <div class="top-menu">
    <h1>JOSHUA BROWN</h1>
    <div class="li">
      <ul>
        <li>contact</li>
        <li>news</li>
        <li>concerts</li>
        <li>videos</li>
        <li>photos</li>
        <li>bio</li>
        <li>home</li>
      </ul>
    </div>
  </div>
</body>

</html>

然后在querydsl中你可以使用SELECT g.code AS catcode FROM dwh_aggregated_order AS a INNER JOIN cat_product_category g ON g.id = a.product_category_id GROUP BY g.code HAVING COUNT(g.code) > 2;

在QueryDSL中，可以在where

1 个答案: