Question

这是一个BMI计算器，可根据用户选择的选项计算英制或公制BMI。然后我需要显示他们的BMI状态（体重不足，超重，肥胖）。我在Person类中有一个方法，我想在main方法中调用，但是Visual Studio强调了bmi变量，并说＆＃34;使用未分配的局部变量＆＃34;

如何修复变量问题？

这是类代码：

class Person
{
    double Height { get; set; }
    double Weight { get; set; }
    double Inches { get; set; }
    double Bmi { get; set; }

    public Person()
    {

    }

    public Person(double height, double weight, double bmi)
    {
        Height = height;
        Weight = weight;
        Bmi = bmi;
    }

    public Person (double height, double weight, double inches, double bmi)
    {
        Height = height;
        Weight = weight;
        Inches = inches;
        Bmi = bmi;
    }


    //calculates BMI using metric formula 
    public static double CalcMetric(double height, double weight)
    {
        double bmi = weight / Math.Pow(height, 2);
        return bmi;
    }

    //calculates BMI using imperial formula
    public static double CalcImperial(double height, double weight)
    {
        double bmi = weight / Math.Pow(height, 2) * 703;
        return bmi;
    }

    public void Status(double bmi)
    {
        if (bmi < 18.5)
        {
            Console.WriteLine("Your BMI status is underweight.");
        }
        else
          if (bmi < 24.9)
        {
            Console.WriteLine("Your BMI status is normal.");
        }
        else
          if (bmi < 29.9)
        {
            Console.WriteLine("Your BMI status is overweight.");
        }
        else
          if (bmi > 30)
        {
            Console.WriteLine("Your BMI status is obese.");
        }
    }

}
}

这是主程序

class Program
{
    static void Main(string[] args)
    {
        Console.BackgroundColor = ConsoleColor.White; //set background
        Console.Clear();
        Console.ForegroundColor = ConsoleColor.Black; //set foreground

        string inputHeight;
        string inputWeight;
        string aValue;
        double choice;
        double height;
        double weight;
        double bmi;


        Person p = new Person();

        Console.WriteLine("Welcome to BMI Calculator. \nEnter 1 for imperial calculator, 2 for metric calculator or 3 to quit.");
        aValue = Console.ReadLine();
        choice = double.Parse(aValue);

        if (choice == 1)
        {
            Console.WriteLine("Enter height in inches: ");
            inputHeight = Console.ReadLine();

            Console.WriteLine("Enter weight in lbs: ");
            inputWeight = Console.ReadLine();

            height = double.Parse(inputHeight);
            weight = double.Parse(inputWeight);

            Console.WriteLine("Your BMI is: " + Person.CalcImperial(height, weight));
        }
        else
                if (choice == 2)
        {
            Console.WriteLine("Enter height in meters: ");
            inputHeight = Console.ReadLine();

            Console.WriteLine("Enter weight in kilos: ");
            inputWeight = Console.ReadLine();

            height = double.Parse(inputHeight);
            weight = double.Parse(inputWeight);

            Console.WriteLine("Your BMI is: " + Person.CalcMetric(height, weight));
        }
        else
                if (choice == 3)
        {
            Console.WriteLine("Goodbye!");
        }

        p.Status(bmi);



        Console.ReadKey();

            }



        }

Answer 1

您收到错误，因为double bmi;未初始化。根据引导线方法，成员需要在方法中初始化，您不能只声明它。所以你需要这样做

double bmi=0;

检查一下：Are C# uninitialized variables dangerous?

您的代码还有一个问题，

//in your person class
public void Status(double bmi)
{
}

你正在做p.Status(ref bmi);，你不会得到更新的值，因为double是在函数中完成的值类型更改而不是反映实际值，你需要这样做，

//in your person class
public void Status(ref double bmi)
{
}

在参考的帮助下，你将从函数中获得价值。

更好的解决方案是从函数返回值

//in your person class
public double Status()
{
     double bmi=0;
    //rest of code 
    return bmi;
}

主bmi = p.Status();

中的

Answer 2

Bmi是人类的内部成员（默认情况下），因此您不能直接使用BMI而是使用

Status(CalcMetric); or `status(CalcImperial);` *according to your requirement*

这样这些函数在函数调用期间返回BMI的值。

如何在主程序中正确调用此方法？

2 个答案: