我正在尝试创建一个返回具有相同名称的行的查询。
查询
left outer join fgt_ext_admin_managed_lov a <<<
..
..
inner join fgt_address a <<<<
我明白了:
SELECT
version,
name,
count (version) OVER (PARTITION BY name)
FROM
application
WHERE id = 123;
虽然预期结果是:
version | name | count
---------+----------------------+-------
29.0 | Mouser | 2
28.0 | Mouser | 2
11.0 | Niche Norman | 1
| Galaxy Creator | 0
| Cube Generator | 0
但是当我使用 version | name | count
---------+----------------------+-------
29.0 | Mouser | 2
28.0 | Mouser | 2
时,它什么都不返回。
答案 0 :(得分:0)
你不能在窗口聚合中使用HAVING:
SELECT *
FROM
(
SELECT
version,
name,
count (version) OVER (PARTITION BY name) as cnt
FROM
application
WHERE id = 123
) as dt
WHERE cnt > 2;