Question

我一直在尝试对以下程序进行编码，以便当用户输入＆＃34;停止＆＃34;或者＆＃34; s＆＃34;，程序将终止，但直到他输入该单词，它将继续要求用户输入数字以平方根。这是我的代码到目前为止，在功能方面它很好，但我似乎无法做到这一点。谢谢大家。

import java.util.Scanner;

public class Question5 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        double input, var = 0.0, var2 = 0.0; //initialising variables
        String x;

        System.out.println("Input the number to calculate square root on");
        input = sc.nextDouble(); //inputting by the user


        while(!x.equals("stop")) {

            x = sc.next();
            if (input < 0) { //negative numbers cannot be entered
                System.out.println("Negative numbers are not computable in this case");
                System.exit(1);
            }
            double RepeatedInp = input;

            while (true) {
                //calculation of square root of number inputted
                var = ((RepeatedInp + input / RepeatedInp) / 2.0);
                RepeatedInp = var;

                if (var2 == var) {
                    break;
                }


                var2 = var;
            }
            System.out.println(var); //printing


        }


    }
}

Answer 1

您可以使用Scanner或BufferReader。这里有很多细节：Scanner vs. BufferedReader

使用扫描仪：它等待行尾（您必须按返回）。

// INPUT LOOP

System.out.println（“输入你的公式（停止停止）：”）;

Scanner s = new Scanner(System.in);
String line;

while ((line=s.nextLine())!=null)
     {
    System.out.println("LINE:'"+line+"'"); 


        // IF STOP: 
        if (line.contentEquals("stop"))
            break;

        if (line.contentEquals("s"))
            break;

        // do what you want

         System.out.println("TYPE YOUR FORMULA (s ou stop to STOP):"); 

         } 
        // while ((line=s.nextLine())!=null)

 // safe
 s.close();

要直接获取字符，请参阅：How to read a single char from the console in Java (as the user types it)?

循环直到用户输入＆＃34;停止＆＃34;

1 个答案: