Question

我正在开发一个“游戏”，供用户猜测一个随机的两位数字，这是我迄今为止的“强大”版本：

import static java.lang.System.*;
import java.util.*;

public class RandomNumberGuessing {

public static Scanner scan = new Scanner(in);

public static void main(String args[]){
    Random generator = new Random ();
    int Low = 10;
    int High = 99;
    int answer = generator.nextInt (High - Low) + Low;
    int answerFirstDigit = Integer.parseInt(String.valueOf(answer).substring(0,1));
    int answerSecondDigit = Integer.parseInt(String.valueOf(answer).substring(1,2));
    int count = 0;
    out.println ("Welcome to the two digit number guessing game!");
    out.println ("We have randomly chosen a two-digit number");
    out.println ("And you have to guess it after 5 tries!");
    out.println ("Guess the number: ");
    while (!scan.hasNextInt ()) {
        scan.next ();
        out.println ("You have to input a valid two-digit integer!");
    }
    int guess = scan.nextInt ();
    while (guess != answer && count < 4){
        count ++;
        out.println("Wrong number! You have " + (5 - count) + " tries left:");
        if (Integer.parseInt(String.valueOf(guess).substring(0,1)) == answerFirstDigit){
            out.println("But you got the first digit correctly!");
        } else if (Integer.parseInt(String.valueOf(guess).substring(1,2)) == answerSecondDigit){
            out.println("But you got the second digit correctly!");
        } else if (Integer.parseInt(String.valueOf(guess).substring(1,2)) == answerSecondDigit || Integer.parseInt(String.valueOf(guess).substring(0,1)) == answerSecondDigit){
            out.println("One or two digits are correct but in the wrong place!");
        }
        while (!scan.hasNextInt ()) {
            scan.next ();
            out.println ("You have to input a valid two-digit integer!");
        }
        guess = scan.nextInt ();
    }
    if (guess == answer){
        out.println("Congratulations! The number was " + answer + "!");
    } else{
        out.println("The number was " + answer + ". Better luck next time!");
    }
}

}

但我在强迫用户输入两位数字时遇到问题。我尝试使用：

while(guess < 10 || guess > 99){
   scan.next();
   out.println("Invalid number!");
   guess = scan.nextInt();
}

我添加了while循环以确保用户输入一个整数，当我在控制台中输入一个3位或4位数字时（我在IntelliJ IDEA上运行代码），它似乎挂起了没有响应。它甚至没有打印出“无效的号码！”然后挂起我是否必须使用方法重写代码，还是我可以添加到现有代码以确保用户输入TWO-DIGIT INTEGER？提前致谢

Answer 1

要检查用户只输入两位数字，我会使用两种方法来验证。要检查的事项：

用户必须输入内容，即不接受空或空
用户输入的所有内容必须正好两个字符
当字符为2时，它们必须全部为数字

在您的计划中，您可以执行这些操作 1.输入字符串
2.调用validString
3.如果有效，则转换为整数
4.检查该数字是否在范围之间（如果用户输入01，则评估为真）。 Integer.ParseInt可以抓住这个，但无论如何都要检查

完整的程序应该是这样的

import static java.lang.System.*;
import java.util.*;

public class RandomNumberGuessing {

public static Scanner scan = new Scanner(in);

public static void main(String args[]) {
    final int tries = 5; // max number of tries
    Random generator = new Random();
    int Low = 10;
    int High = 99;
    int answer = generator.nextInt(High - Low) + Low;

    int firstDigit = getFirst(answer);
    int secondDigit = getSecond(answer);

    out.println("Welcome to the two digit number guessing game!");
    out.println("We have randomly chosen a two-digit number");
    out.println("And you have to guess it after " + tries + " tries!");

    int guess = 0; // number guessed
    int count = 0; // number of failed guesses

    do {
        out.println("Guess the number: ");

        String guessString = scan.nextLine(); // just read everything
                                              // entered

        if (validString(guessString)) {
            guess = Integer.parseInt(guessString);
            if (guess >= Low && guess <= High) { // check range and only
                                                 // process valid range
                count++;
                if (count == tries) {
                    out.print("Max guess reached.\nThe values were ");
                    out.println(firstDigit + " and " + secondDigit);
                    break;
                }
                out.println("You guessed " + guess);

                // get the first and second digits
                int first = getFirst(guess);
                int second = getSecond(guess);

                // compare them and process
                if (guess == answer) {
                    out.println("Congratulations. You made the right guess after "
                                    + count + " tries");
                } else if (first == firstDigit) {
                    out.println("Guessed the first number rightly");

                } else if (second == secondDigit) {
                    out.println("Guessed the second number rightly");
                } else {
                    out.print("No matching guess. You have ");
                    out.println((tries - count) + " guesses left");
                }
            } else {
                out.println("Out of range!");
            }

        } else {
            out.println("Bad Value.");

        }

    } while (guess != answer && count < tries);

}

// Validate an input Checks for length [2 characters] and that everything is
// a digit
private static boolean validString(final String guess) {
    if (guess != null && !guess.isEmpty()) { // if not null and not empty

        if (guess.length() == 2 && isAllDigits(guess)) { // length and digit
            return true;
        } else {
            return false;
        }
    } else {
        return false;
    }
}

// Verify that all characters in a string are numbers
private static boolean isAllDigits(final String input) {
    for (char c : input.toCharArray()) {
        if (!Character.isDigit(c))
            return false;
    }
    return true;
}

// get the first digit
private static int getFirst(final int value) {
    return Integer.parseInt(String.valueOf(value).substring(0, 1));
  }

// Get the second digit
private static int getSecond(final int value) {
    return Integer.parseInt(String.valueOf(value).substring(0, 1));
    }
}

Java中的随机两位数猜数游戏

1 个答案: