从12月到12月获取AVG SQL
我有这张桌子（例子）：
http://www.sqlfiddle.com/#!9/412b11/1
我需要根据年份在AnualAmount列中插入全年+去年12月的平均值，这是我必须使用示例数据获得的结果：
因此，在2018年的所有时期，我必须在AnualAmount中插入全年的AVG +去年12月的金额，以及其他硬币和年份等等。
2 个答案:
答案 0 :(得分：2)
有点笨重，但我认为它有效
declare @T table (Period int, Coin varchar(3), Amount int, AnualAmount varchar(4));
INSERT INTO @T (Period, Coin, Amount, AnualAmount) VALUES
(201701, 'MXP', 13.5, NULL),
(201702, 'MXP', 14.5, NULL),
(201703, 'MXP', 15.5, NULL),
(201704, 'MXP', 16.5, NULL),
(201705, 'MXP', 17.5, NULL),
(201706, 'MXP', 18.5, NULL),
(201707, 'MXP', 19.5, NULL),
(201708, 'MXP', 20.5, NULL),
(201709, 'MXP', 21.5, NULL),
(201710, 'MXP', 22.5, NULL),
(201711, 'MXP', 23.5, NULL),
(201712, 'MXP', 24.5, NULL),
(201801, 'MXP', 25.5, NULL),
(201802, 'MXP', 26.5, NULL),
(201803, 'MXP', 27.5, NULL),
(201804, 'MXP', 28.5, NULL),
(201805, 'MXP', 29.5, NULL),
(201806, 'MXP', 30.5, NULL),
(201807, 'MXP', 31.5, NULL),
(201808, 'MXP', 32.5, NULL),
(201809, 'MXP', 33.5, NULL),
(201810, 'MXP', 34.5, NULL),
(201811, 'MXP', 35.5, NULL),
(201812, 'MXP', 36.5, NULL),
(201701, 'COP', 37.5, NULL),
(201702, 'COP', 38.5, NULL),
(201703, 'COP', 39.5, NULL),
(201704, 'COP', 40.5, NULL),
(201705, 'COP', 41.5, NULL),
(201706, 'COP', 42.5, NULL),
(201707, 'COP', 43.5, NULL),
(201708, 'COP', 44.5, NULL),
(201709, 'COP', 45.5, NULL),
(201710, 'COP', 46.5, NULL),
(201711, 'COP', 47.5, NULL),
(201712, 'COP', 48.5, NULL),
(201801, 'COP', 49.5, NULL),
(201802, 'COP', 50.5, NULL),
(201803, 'COP', 51.5, NULL),
(201804, 'COP', 52.5, NULL),
(201805, 'COP', 53.5, NULL),
(201806, 'COP', 54.5, NULL),
(201807, 'COP', 55.5, NULL),
(201808, 'COP', 56.5, NULL),
(201809, 'COP', 57.5, NULL),
(201810, 'COP', 58.5, NULL),
(201811, 'COP', 59.5, NULL),
(201812, 'COP', 60.5, NULL),
(201701, 'REA', 61.5, NULL),
(201702, 'REA', 62.5, NULL),
(201703, 'REA', 63.5, NULL),
(201704, 'REA', 64.5, NULL),
(201705, 'REA', 65.5, NULL),
(201706, 'REA', 66.5, NULL),
(201707, 'REA', 67.5, NULL),
(201708, 'REA', 68.5, NULL),
(201709, 'REA', 69.5, NULL),
(201710, 'REA', 70.5, NULL),
(201711, 'REA', 71.5, NULL),
(201712, 'REA', 72.5, NULL),
(201801, 'REA', 73.5, NULL),
(201802, 'REA', 74.5, NULL),
(201803, 'REA', 75.5, NULL),
(201804, 'REA', 76.5, NULL),
(201805, 'REA', 77.5, NULL),
(201806, 'REA', 78.5, NULL),
(201807, 'REA', 79.5, NULL),
(201808, 'REA', 80.5, NULL),
(201809, 'REA', 81.5, NULL),
(201810, 'REA', 82.5, NULL),
(201811, 'REA', 83.5, NULL),
(201812, 'REA', 84.5, NULL);
declare @D table (Period int);
INSERT INTO @D (Period) values
(201712),
(201801),
(201802),
(201803),
(201804),
(201805),
(201806),
(201807),
(201808),
(201809),
(201810),
(201811),
(201812);
select t.Coin, t.Period, t.Amount
, AVG(t.Amount) over (partition by t.Coin) as Annual
from @T t
join @D d
on t.Period = d.Period
union all
select t.Coin, t.Period, t.Amount
, null
from @T t
left join @D d
on t.Period = d.Period
where d.Period is null
order by Coin, Period;
Coin Period Amount Annual
---- ----------- ----------- -----------
COP 201701 37 NULL
COP 201702 38 NULL
COP 201703 39 NULL
COP 201704 40 NULL
COP 201705 41 NULL
COP 201706 42 NULL
COP 201707 43 NULL
COP 201708 44 NULL
COP 201709 45 NULL
COP 201710 46 NULL
COP 201711 47 NULL
COP 201712 48 54
COP 201801 49 54
COP 201802 50 54
COP 201803 51 54
COP 201804 52 54
COP 201805 53 54
COP 201806 54 54
COP 201807 55 54
COP 201808 56 54
COP 201809 57 54
COP 201810 58 54
COP 201811 59 54
COP 201812 60 54
MXP 201701 13 NULL
MXP 201702 14 NULL
MXP 201703 15 NULL
MXP 201704 16 NULL
MXP 201705 17 NULL
MXP 201706 18 NULL
MXP 201707 19 NULL
MXP 201708 20 NULL
MXP 201709 21 NULL
MXP 201710 22 NULL
MXP 201711 23 NULL
MXP 201712 24 30
MXP 201801 25 30
MXP 201802 26 30
MXP 201803 27 30
MXP 201804 28 30
MXP 201805 29 30
MXP 201806 30 30
MXP 201807 31 30
MXP 201808 32 30
MXP 201809 33 30
MXP 201810 34 30
MXP 201811 35 30
MXP 201812 36 30
REA 201701 61 NULL
REA 201702 62 NULL
REA 201703 63 NULL
REA 201704 64 NULL
REA 201705 65 NULL
REA 201706 66 NULL
REA 201707 67 NULL
REA 201708 68 NULL
REA 201709 69 NULL
REA 201710 70 NULL
REA 201711 71 NULL
REA 201712 72 78
REA 201801 73 78
REA 201802 74 78
REA 201803 75 78
REA 201804 76 78
REA 201805 77 78
REA 201806 78 78
REA 201807 79 78
REA 201808 80 78
REA 201809 81 78
REA 201810 82 78
REA 201811 83 78
REA 201812 84 78
答案 1 :(得分：1)
您可以尝试以下更新。在这里，我们强制将前一个月纳入下一年，因此可能有一段时间（按硬币计算），包括长达13个月。请注意，我将Amount和AnnualAmount数据类型更改为DECIMAL（因为您使用的是小数而不仅仅是整数）。此外，12月份用于2个不同的平均值（当前和明年），在此查询中，我们正在更新当前年份的年度安装量。
IF OBJECT_ID('tempdb..#Table') IS NOT NULL
DROP TABLE #Table
CREATE TABLE #Table (
Period int,
Coin varchar(3),
Amount DECIMAL(8,2),
AnnualAmount DECIMAL(8,2))
INSERT INTO #Table (Period, Coin, Amount, AnnualAmount)
VALUES
(201701, 'MXP', 13.5, NULL),
(201702, 'MXP', 14.5, NULL),
(201703, 'MXP', 15.5, NULL),
(201704, 'MXP', 16.5, NULL),
(201705, 'MXP', 17.5, NULL),
(201706, 'MXP', 18.5, NULL),
(201707, 'MXP', 19.5, NULL),
(201708, 'MXP', 20.5, NULL),
(201709, 'MXP', 21.5, NULL),
(201710, 'MXP', 22.5, NULL),
(201711, 'MXP', 23.5, NULL),
(201712, 'MXP', 24.5, NULL),
(201801, 'MXP', 25.5, NULL),
(201802, 'MXP', 26.5, NULL),
(201803, 'MXP', 27.5, NULL),
(201804, 'MXP', 28.5, NULL),
(201805, 'MXP', 29.5, NULL),
(201806, 'MXP', 30.5, NULL),
(201807, 'MXP', 31.5, NULL),
(201808, 'MXP', 32.5, NULL),
(201809, 'MXP', 33.5, NULL),
(201810, 'MXP', 34.5, NULL),
(201811, 'MXP', 35.5, NULL),
(201812, 'MXP', 36.5, NULL),
(201701, 'COP', 37.5, NULL),
(201702, 'COP', 38.5, NULL),
(201703, 'COP', 39.5, NULL),
(201704, 'COP', 40.5, NULL),
(201705, 'COP', 41.5, NULL),
(201706, 'COP', 42.5, NULL),
(201707, 'COP', 43.5, NULL),
(201708, 'COP', 44.5, NULL),
(201709, 'COP', 45.5, NULL),
(201710, 'COP', 46.5, NULL),
(201711, 'COP', 47.5, NULL),
(201712, 'COP', 48.5, NULL),
(201801, 'COP', 49.5, NULL),
(201802, 'COP', 50.5, NULL),
(201803, 'COP', 51.5, NULL),
(201804, 'COP', 52.5, NULL),
(201805, 'COP', 53.5, NULL),
(201806, 'COP', 54.5, NULL),
(201807, 'COP', 55.5, NULL),
(201808, 'COP', 56.5, NULL),
(201809, 'COP', 57.5, NULL),
(201810, 'COP', 58.5, NULL),
(201811, 'COP', 59.5, NULL),
(201812, 'COP', 60.5, NULL),
(201701, 'REA', 61.5, NULL),
(201702, 'REA', 62.5, NULL),
(201703, 'REA', 63.5, NULL),
(201704, 'REA', 64.5, NULL),
(201705, 'REA', 65.5, NULL),
(201706, 'REA', 66.5, NULL),
(201707, 'REA', 67.5, NULL),
(201708, 'REA', 68.5, NULL),
(201709, 'REA', 69.5, NULL),
(201710, 'REA', 70.5, NULL),
(201711, 'REA', 71.5, NULL),
(201712, 'REA', 72.5, NULL),
(201801, 'REA', 73.5, NULL),
(201802, 'REA', 74.5, NULL),
(201803, 'REA', 75.5, NULL),
(201804, 'REA', 76.5, NULL),
(201805, 'REA', 77.5, NULL),
(201806, 'REA', 78.5, NULL),
(201807, 'REA', 79.5, NULL),
(201808, 'REA', 80.5, NULL),
(201809, 'REA', 81.5, NULL),
(201810, 'REA', 82.5, NULL),
(201811, 'REA', 83.5, NULL),
(201812, 'REA', 84.5, NULL);
;WITH ParsedDates AS
(
SELECT
T.*,
Year = T.Period / 100,
Month = T.Period % 100
FROM
#Table AS T
),
CoinPeriods AS
(
SELECT
P.Amount,
P.Coin,
P.YEAR,
P.Month
FROM
ParsedDates AS P
UNION ALL
SELECT
N.Amount,
N.Coin,
Year = N.YEAR + 1, -- Force previous year's months to be included in next year calculation
N.Month
FROM
ParsedDates AS N
WHERE
N.Month = 12
),
AnnualAmounts AS
(
SELECT
P.Coin,
P.Year,
AnnualAmount = AVG(P.Amount)
FROM
CoinPeriods AS P
GROUP BY
P.Coin,
P.Year
)
UPDATE T SET
AnnualAmount = A.AnnualAmount
FROM
#Table AS T
INNER JOIN AnnualAmounts AS A ON
T.Coin = A.Coin AND
T.Period / 100 = A.Year
/*
SELECT * FROM #Table AS T
Results:
Period Coin Amount AnnualAmount
201701 MXP 13.50 19.00
201702 MXP 14.50 19.00
201703 MXP 15.50 19.00
201704 MXP 16.50 19.00
201705 MXP 17.50 19.00
201706 MXP 18.50 19.00
201707 MXP 19.50 19.00
201708 MXP 20.50 19.00
201709 MXP 21.50 19.00
201710 MXP 22.50 19.00
201711 MXP 23.50 19.00
201712 MXP 24.50 19.00
201801 MXP 25.50 30.50
201802 MXP 26.50 30.50
201803 MXP 27.50 30.50
201804 MXP 28.50 30.50
201805 MXP 29.50 30.50
201806 MXP 30.50 30.50
201807 MXP 31.50 30.50
201808 MXP 32.50 30.50
201809 MXP 33.50 30.50
201810 MXP 34.50 30.50
201811 MXP 35.50 30.50
201812 MXP 36.50 30.50
201701 COP 37.50 43.00
201702 COP 38.50 43.00
201703 COP 39.50 43.00
201704 COP 40.50 43.00
201705 COP 41.50 43.00
201706 COP 42.50 43.00
201707 COP 43.50 43.00
201708 COP 44.50 43.00
201709 COP 45.50 43.00
201710 COP 46.50 43.00
201711 COP 47.50 43.00
201712 COP 48.50 43.00
201801 COP 49.50 54.50
201802 COP 50.50 54.50
201803 COP 51.50 54.50
201804 COP 52.50 54.50
201805 COP 53.50 54.50
201806 COP 54.50 54.50
201807 COP 55.50 54.50
201808 COP 56.50 54.50
201809 COP 57.50 54.50
201810 COP 58.50 54.50
201811 COP 59.50 54.50
201812 COP 60.50 54.50
201701 REA 61.50 67.00
201702 REA 62.50 67.00
201703 REA 63.50 67.00
201704 REA 64.50 67.00
201705 REA 65.50 67.00
201706 REA 66.50 67.00
201707 REA 67.50 67.00
201708 REA 68.50 67.00
201709 REA 69.50 67.00
201710 REA 70.50 67.00
201711 REA 71.50 67.00
201712 REA 72.50 67.00
201801 REA 73.50 78.50
201802 REA 74.50 78.50
201803 REA 75.50 78.50
201804 REA 76.50 78.50
201805 REA 77.50 78.50
201806 REA 78.50 78.50
201807 REA 79.50 78.50
201808 REA 80.50 78.50
201809 REA 81.50 78.50
201810 REA 82.50 78.50
201811 REA 83.50 78.50
201812 REA 84.50 78.50
*/
我同意Tim的意见，因为存储一个依赖于超过1行的计算列是一个糟糕设计的标志（更新一行的Amount将需要重新计算几个AnnualAmount那些）。在这种情况下，最好将此值保存在聚合单独的表中（按年份和硬币），或者只计算它以显示而不是实际存储。
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