$EvtMessage= @"
A member was removed from a security-enabled global group.
Subject:
Security ID: S-1-5-21-1232435678-3215674231-8564287451-324516
Account Name: tstact.ntt.admin
Account Domain: DT
Logon ID: 0x1E3363AEE
Member:
Security ID: S-1-5-21-1523435678-3215674231-8564287451-324516
Account Name: CN=DT DEST02,OU=NoStandard,OU=Users,OU=My Org B2B TEST,DC=DT,DC=ad,DC=local
Group:
Security ID: S-1-5-21-1523435678-3215674231-8564287451-324516
Group Name: TSK-DT-S-D-SRVAdmin
Group Domain: DT
Additional Information:
Privileges:
"@
我需要提取上面“ tstact.ntt.admin ”位置的任何字符串(在主题:下,而不是成员: )使用 -Match 或选择字符串。你能帮我解决一下PowerShell正则表达式吗?
提前致谢
答案 0 :(得分:1)
可能不是完美的解决方案,但我最终得到了以下内容:
@($ EvtMessage -split [environment] :: NewLine)[4] -match'。帐户名称:(?。)$'
<强> $ matches.AccountName 强>
此解决方案假定消息结构的格式(就各行而言)不会更改。手指交叉......