Question

我正在尝试编写一些内容，我首先在txt文件中查找一行中的字符串，当找到它时，我想跳过该行和下面的行以获取没有这些行的新txt文件。我真的没有从其他问题得到任何解决方案，所以也许这将工作

我的代码现在看起来像这样：

with open("bla.txt", "r+") as f
    new_f = f.readlines()
    f.seek(0)
    for line in new_f:
        if "abc" not in line:
            f.write(line)
        else:
            pass
            pass
    f.truncate()

我用next(f)尝试过，但它对我不起作用。提前谢谢

Answer 1

如果当前行包含字符串ABC：

，此代码将创建一个跳过当前行和下一行的新文件

with open('bla.txt','r') as f:
    text = f.read()
    lines = text.split('\n')
with open('new_file.txt','w') as nf:
    l = 0
    while l<(len(lines)):
        if 'ABC' in lines[l]:
            l = l+2
        else:
            nf.write(lines[l]+'\n')
            l = l+1

Answer 2

尝试这样简单的事情：

import os

search_for = 'abc'

with open('input.txt') as f, open('output.txt', 'w') as o:
  for line in f:
    if search_for in line:
       next(f) # we need to skip the next line
               # since we are already processing
               # the line with the string
               # in effect, it skips two lines
    else:
       o.write(line)

os.rename('output.txt', 'input.txt')

这是repl with sample code。

在从文件中读取时匹配后跳过2行

2 个答案: