Question

我有一个电影数据字典，我想创建一个新字典，其中包含预算和收入键值大于0.0的电影子集。

这是我的代码，有人可以帮忙吗？

movies_bud_rev = {}
for movie in movie_data:
    if (movie_data['revenue'] != 0.0 or movie_data['budget'] != 0.0):
        id = movie_data['id']
        budget = movie_data['budget']   
        revenue = movie_data['revenue']
        original_title = movie_data['original_title']
        release_year = movie_data['release_year']
        genre = movie_data['genre']
        popularity = movie_data['popularity']
        vote_average = movie_data['vote_average']
        vote_count = movie_data['vote_count']

len (movies_bud_rev)

我收到的错误：

TypeError: list indices must be integers, not str

我的字典 enter image description here

我尝试创建新词典 enter image description here

Answer 1

根据您提供的图片，<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="arrow"></div> <div class="arrow active"></div>为list of dictionaries。

因此，您需要将过滤为列表。您可以通过列表理解来实现这一目标。

movie_data

请注意一些问题：

结果也将是一个词典列表。
收入和预算大于零的逻辑需要使用res = [m for m in movie_data if (m['revenue'] > 0 and m['budget'] > 0)]，而不是and。

Answer 2

根据您发布的图片movie_data是包含字典的列表并且你在movie_data中使用了索引，这就是你在movie中获取错误的原因，这是字典对象

movies_bud_rev = {}
for movie in movie_data:
    if (movie['revenue'] != 0.0 or movie['budget'] != 0.0):
        id = movie['id']
        budget = movie['budget']   
        revenue = movie['revenue']
        original_title = movie['original_title']
        release_year = movie['release_year']
        genre = movie['genre']
        popularity = movie['popularity']
        vote_average = movie['vote_average']
        vote_count = movie['vote_count']

当键值大于0时，创建字典列表

2 个答案: