Question

使用以下查询：

SELECT title, nid, created FROM node WHERE uid = $account->uid ORDER BY changed DESC

如何打印标题，nid，单独创建（用PHP）？

谢谢！（我确定这很简单，我还不习惯PHP）

Answer 1

这是一个非常基本的问题，请尝试使用google进行教程。这是关于PHP和mysql的第一个google结果的c / p，它显示了你所追求的技术。

// Retrieve all the data from the "example" table
$result = mysql_query("SELECT * FROM example")
or die(mysql_error());  

// store the record of the "example" table into $row
$row = mysql_fetch_array( $result );
// Print out the contents of the entry 

echo "Name: ".$row['name'];
echo " Age: ".$row['age'];

http://www.tizag.com/mysqlTutorial/mysqlquery.php

Answer 2

如果您只期望一个结果：

$query = "SELECT title, nid, created FROM node WHERE uid = '".$account->uid."' ORDER BY changed DESC";
$resource = mysql_query($query) or die (mysql_error());

if(mysql_num_rows($resource)>0)
{

   $row = mysql_fetch_array($resource);
   echo 'Title: '.$row['title'].'<br />';
   echo 'ID: '.$row['nid'].'<br />';
}
else
{
  echo 'no record found';
}

否则（我现在重读了问题的标题，对不起）

while ($row = mysql_fetch_array($resource))
{
      echo 'Title: '.$row['title'].'<br />';
      echo 'ID: '.$row['nid'].'<br />'; 
}

单独打印多个列

2 个答案: