Question

我在将数据插入现有SQL Server表时遇到问题。

IF OBJECT_ID('Coinmarketcap.dbo.tbl_ATR', 'U') IS NOT NULL 
    DROP TABLE Coinmarketcap.dbo.tbl_ATR;   

SELECT
    [Ticker],[Date],[px_high], [px_low], [px_close],[yest_close],
    ATR_spd = iif([px_high] > yest_close, [px_high], yest_close) - iif([px_low] > yest_close, yest_close, [px_low]),
    ATR1 = (iif([px_high] > yest_close, [px_high], yest_close) - iif([px_low] > yest_close, yest_close, [px_low])) / (iif(yest_close = 0 , 1 , yest_close))
FROM 
    (SELECT 
         *, yest_close = lag([px_close]) OVER (PARTITION BY Ticker ORDER BY [Date])
     FROM 
         [Coinmarketcap].[dbo].[daily_data]) t
INTO 
    [Coinmarketcap].[dbo].[tbl_ATR]
ORDER BY 
    [Ticker] ASC, [Date] DESC

我无法确定INTO语句的放置位置。

关键字＆＃39; INTO＆＃39;。
附近的语法不正确

还尝试INSERT INTO声明无济于事。

Answer 1

稍微关闭......并且您不需要订单，因为您丢弃了表并且它被存储为无序集（因为您没有在此处应用索引）。我假设你想从结果中继承定义。这是使用SELECT ... INTO TABLE ... FROM TABLE而不是INSERT INTO TABLE ... SELECT ... FROM TABLE

IF OBJECT_ID('Coinmarketcap.dbo.tbl_ATR', 'U') IS NOT NULL 
DROP TABLE Coinmarketcap.dbo.tbl_ATR; 

SELECT
    [Ticker],
    [Date],
    [px_high], 
    [px_low], 
    [px_close],
    [yest_close],
    ATR_spd = iif([px_high] > yest_close, [px_high], yest_close) - iif([px_low] > yest_close, yest_close, [px_low]),
    ATR1 = (iif([px_high] > yest_close, [px_high], yest_close) - iif([px_low] > yest_close, yest_close, [px_low])) / (iif(yest_close = 0 , 1 , yest_close))
INTO [Coinmarketcap].[dbo].[tbl_ATR]
FROM (
    SELECT 
        *, 
        yest_close = lag([px_close]) OVER (PARTITION BY Ticker ORDER BY [Date])
    FROM [Coinmarketcap].[dbo].[daily_data]
) t

注意，你做不到......

INSERT INTO TABLE
SELECT FROM SomeTable

首先没有明确创建该表。我使用上面的SELECT INTO，因为你在声明之前删除了表。

将数据插入现有SQL Server表

1 个答案: