Question

所以我试图获得此输出

No Column Sum
0 Company 28
1 Booth 28
2 Full-Time 25
3 Full-Time Visa Sponsor 5
4 Part-Time 1
5 Internship 18
6 Freshman 7
7 Sophomore 9
8 Junior 17
9 Senior 24
10 Post-Bacs 17
11 MS 17
12 PhD 6
13 Alumni 15

但是，我收到此错误

TypeError：元组索引必须是整数或切片，而不是str

我的代码如下

data_employer = {'No': ('Column', 'Sum')}
for vari in range(14):
    sum = 0
    for row in ReadyColumn:
        if row[vari] != '':
            sum =+1
        data_employer = (companies[vari], sum)
for num in data_employer:
    print(num, data_employer [num][0], data_employer[num][1])
outData = []

是因为我不需要调用num而是行号吗？我认为它可以这样工作。任何输入将不胜感激。谢谢！

Traceback (most recent call last):
  File "/Prj3Assignt3.py", line 42, in <module>
    print(num, data_employer[num][0], data_employer[num][1])
TypeError: tuple indices must be integers or slices, not str

添加了错误

import csv
filename = "CFSpring2018Employers.csv"                         #I assigned the file to a variable
f = open(filename)                        #I couldn't leave it default due to UTF-8 error from orginial
reader = csv.reader(f)
f.close

#Dictionary for part 1 'Companies'
companies = {}
countComp = 0 #Sets the 'rows to 0

for row in reader: #reader has assigned value to read csv info
    if row[0] == 'Company': #Searches row called 'Company'
        for item in row:
            companies[countComp] = item #Everytime it shows it puts it into the dictionary
            countComp += 1
        break

for i in companies: #Allows me to print numbers next to the companies dict
    print(i, companies[i])

ReadyColumn = []    #Making a new list for cleaned up data
NumCow = 0
for row in reader:
    NumCow +=1
    if NumCow > 0 and NumCow < 31 and row[0] != '': #This will read the rows between 0-31, and if the row contains 'Nothing' it skips
        ReadyColumn.append(row) #Updates the list
rowNum = -1 #Resets the counter

for row in ReadyColumn:
    rowNum += 1
    print(rowNum, ','.join(row)) #Joins any weird marks and prints as desired output

data_employer = {'No', 'Column', 'Sum'}
for vari in range(14):
    sum = 0
    for row in ReadyColumn:
        if row[vari] != '':
            sum =+1
        cleaner_employer = (companies[vari], sum)
for i in data_employer:
    print(i, data_employer,i[0], data_employer,i[1])

所以这是我写的代码，以帮助实现这一点。我正在阅读没有 PANDAS 的csv文件（因为我不能将它们用于项目）

Answer 1

您将函数中间的data_employer重新定义为元组：data_employer = (companies[vari], sum)。使用其他名称来避免这种情况。

在以下代码中：

for num in data_employer:
    print(num, data_employer [num][0], data_employer[num][1])

num将首先为companies[vari]，然后为sum。 companies[vari]可能是一个字符串。元组只能使用整数访问。 dict可以通过密钥访问（任何可哈希的对象）。

Answer 2

TL; DR：您正在覆盖变量名称并更改其数据类型。

你用元组覆盖了你的字典！让我们来看看......

首先，您的代码包含注释：

data_employer = {'No': ('Column', 'Sum')} # original dictionary
for vari in range(14):
    sum = 0
    for row in ReadyColumn: # no idea what ReadyColumn is...post this?
        if row[vari] != '':
            sum =+1
        data_employer = (companies[vari], sum) # the issue occurs here!!!
for num in data_employer:
    print(num, data_employer [num][0], data_employer[num][1]) # where you get TypeError
outData = []

显然省略了代码（显示ReadyColumn和companies;两者似乎都是某种形式的迭代）;但我们仍然可以解决这个问题。

首先，您声明并定义一个名为data_employer的字典：

data_employer = {'No': ('Column', 'Sum')}

然而，在你的循环中，你最终用元组替换了这个名字！

data_employer = (companies[vari], sum)

这样想：

>>> data_employer = {'No': ('Column', 'Sum')}
>>> isinstance(data_employer, dict)
True
>>> data_employer = (companies[vari], sum)
>>> isinstance(data_employer, dict)
False
>>> isinstance(data_employer, tuple)
True

当您尝试通过[num]访问它时，它已经从密钥访问（通常是字典）更改为索引访问（通常是元组）。

来自数据收集的TypeError

2 个答案: