Question

我有这段代码：

SELECT
    SUM(SUM(INCOME))OVER(ORDER BY TO_DATE(TO_CHAR(PAYMENT_DATE, 'MM/YYYY'), 'MM/YYYY'))
        AS CUMULATIVE_INCOME,
    SUM(SUM(EXPENSE))OVER(ORDER BY TO_DATE(TO_CHAR(PAYMENT_DATE, 'MM/YYYY'), 'MM/YYYY'))
        AS CUMULATIVE_EXPENSE,
    SUM(INCOME) AS TOTAL_MONTH_INCOME,
    SUM(EXPENSE) AS TOTAL_MONTH_EXPENSE,
    TO_CHAR(PAYMENT_DATE, 'MM/YYYY') AS MONTH
FROM 
   V_CFW_CASH_FLOW
GROUP BY TO_CHAR(PAYMENT_DATE, 'MM/YYYY')
ORDER BY TO_DATE(MONTH, 'MM/YYYY') ASC

我想要的是另一个列，其中包含减去累计收入的结果 - 累计费用。

我尝试了下一个但没有工作：

    SUM(SUM(INCOME))OVER(ORDER BY TO_DATE(TO_CHAR(PAYMENT_DATE, 'MM/YYYY'), 'MM/YYYY'))
    - SUM(SUM(EXPENSE))OVER(ORDER BY TO_DATE(TO_CHAR(PAYMENT_DATE, 'MM/YYYY'), 'MM/YYYY'))
    AS NET,

Answer 1

使用公用表表达式：

WITH cteSUMS AS (SELECT TO_CHAR(PAYMENT_DATE, 'MM/YYYY') AS MONTH,
                        SUM(SUM(INCOME))
                           OVER (ORDER BY TO_DATE(TO_CHAR(PAYMENT_DATE, 'MM/YYYY'), 'MM/YYYY'))
                           AS CUMULATIVE_INCOME,
                        SUM(SUM(EXPENSE))
                          OVER (ORDER BY TO_DATE(TO_CHAR(PAYMENT_DATE, 'MM/YYYY'), 'MM/YYYY'))
                          AS CUMULATIVE_EXPENSE,
                        SUM(INCOME) AS TOTAL_MONTH_INCOME,
                        SUM(EXPENSE) AS TOTAL_MONTH_EXPENSE
                   FROM V_CFW_CASH_FLOW
                   GROUP BY TO_CHAR(PAYMENT_DATE, 'MM/YYYY'))
SELECT MONTH,
       CUMULATIVE_INCOME,
       CUMULATIVE_EXPENSE,
       TOTAL_MONTH_INCOME,
       TOTAL_MONTH_EXPENSE,
       TOTAL_MONTH_INCOME - TOTAL_MONTH_EXPENSE AS NET
  FROM cteSUMS
  ORDER BY TO_DATE(MONTH, 'MM/YYYY') ASC

如果需要，可以使用两个公用表表达式使其更清晰：

WITH cteDATA AS (SELECT TO_CHAR(PAYMENT_DATE, 'MM/YYYY') AS MONTH,
                        INCOME,
                        EXPENSE
                   FROM V_CFW_CASH_FLOW),
     cteSUMS AS (SELECT MONTH,
                        SUM(SUM(INCOME))
                           OVER (ORDER BY TO_DATE(MONTH, 'MM/YYYY'))
                           AS CUMULATIVE_INCOME,
                        SUM(SUM(EXPENSE))
                          OVER (ORDER BY TO_DATE(MONTH, 'MM/YYYY'))
                          AS CUMULATIVE_EXPENSE,
                        SUM(INCOME) AS TOTAL_MONTH_INCOME,
                        SUM(EXPENSE) AS TOTAL_MONTH_EXPENSE
                   FROM cteDATA
                   GROUP BY MONTH)
SELECT MONTH,
       CUMULATIVE_INCOME,
       CUMULATIVE_EXPENSE,
       TOTAL_MONTH_INCOME,
       TOTAL_MONTH_EXPENSE,
       TOTAL_MONTH_INCOME - TOTAL_MONTH_EXPENSE AS NET
  FROM cteSUMS
  ORDER BY TO_DATE(MONTH, 'MM/YYYY') ASC

祝你好运。

如何在oracle查询中减去两个累积聚合cloumn

1 个答案: