我希望循环显示给定2个财政年度之间的所有年份。
如果给定的年份是:2006-07
到2010-11
,我希望显示所有这些年来在这些年和那两年之间也是如此。
预期产出:2006-07, 2007-08, 2008-09, 2009-10, 2010-11
。我尝试在PHP中使用for loop
每年递增一次,但是它很长很笨拙。
答案 0 :(得分:0)
你可以这样做
//year to start with
$startdate = 1960;
//year to end with - this is set to current year. You can change to specific year
$enddate = date("Y");
$years = range ($startdate,$enddate);
//print years
foreach($years as $year)
{
echo $year . "<br />";
echo $year.' - '. (substr($year,-2)+1)."<br />";
echo $year.' - '. str_pad((substr($year,-2)+1), 2 , "0",STR_PAD_LEFT)."<br />";
}
答案 1 :(得分:0)
应该是这样的:
$startdate = 1960;
//year to end with - this is set to current year. You can change to specific year
$enddate = 1970;
$years = range($startdate, $enddate);
//print years
foreach ($years as $year) {
if ((substr($year, -2) + 1) <= substr($enddate, -2)) {
echo $year . ' - ' . (substr($year, -2) + 1) . "<br />";
}
}
答案 2 :(得分:0)
您可以使用以下代码。
// Start Year
$start_year = 1960;
//End Year
$end_year = 1970;
$all_years = range($start_year, $end_year);
array_walk($all_years, function(&$year){
$year = $year .'-'. str_pad((substr($year, -2) + 1),2,"0",STR_PAD_LEFT);
});
print_r($all_years);