Question

我有这个代码应该将我的网站连接到我在xampp中创建的数据库。

<?php

define('DB_HOST', 'localhost');
define('DB_NAME', 'anyons');
define('DB_USER','root');
define('DB_PASSWORD','');


$field1_name=$_POST['email'];
$field2_name=$_POST['pass'];
$field3_name=$_POST['name'];
$con=mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD)or die("Failed to connect to 
MySQL: " . mysql_error());
@mysqli_select_db(DB_NAME,$con) or die( "Unable to select database");
$query = "INSERT INTO login VALUES('$field1_name','$field2_name',
'$field3_name')";mysql_query($query);mysql_close();
?>

我收到错误无法选择数据库，这意味着某处连接断开。我一直想弄清楚，但我真的不能。帮助将受到高度赞赏。

Answer 1

您已合并mysqli和mysql

使用的连接

按照以下代码替换您的代码

<?php
define('DB_HOST', 'localhost');
define('DB_NAME', 'anyons');
define('DB_USER','root');
define('DB_PASSWORD','');

$con = mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,DB_NAME);
// connection checking
if (mysqli_connect_errno()) {
    die("Failed to connect to MySQL: " . mysqli_connect_error());
}
// filtering values
extract($_POST); // collected all post values
$email = mysqli_real_escape_string($con, $email);
$pass = mysqli_real_escape_string($con, $pass);
$name = mysqli_real_escape_string($con, $name);

$query = "INSERT INTO login (email, pass, name) VALUES ('{$email}','{$pass}','{$name}')";
if(!mysqli_query($con, $query)){
    die('Error: ' . mysqli_error($con));
}else{
    echo 'records added!';
}
mysqli_close($con);
?>

在xampp中连接到mysql数据库的问题

1 个答案: