Question

以下是我的控制器操作：

HTTPGET

// GET: ControllerName/Create
[Route("CreateDocument/{personId}")]
public ActionResult Create(int personId)
{
    var personDocumentation = new PersonDocumentation()
    {
        PersonId = pilotId
    };
    ViewBag.DocumentationTypeIdSelection = new SelectList(db.DocumentationTypes, "Id", "DocumentationTypeName");

    return View(personDocumentation);
}

HttpPost

[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Include = "Id,PersonId,DateReceived,DocumentationTypeId,Filepath")] PersonDocumentation personDocumentation)
{
    if (ModelState.IsValid)
    {
        if (Request.Files.Count > 0)
        {
            // performing stuff here
        }

        db.PersonDocumentations.Add(personDocumentation);
        db.SaveChanges();
        return RedirectToAction("Index", "PersonDocumentations", new {pilotId = personDocumentation.PilotId});
    }

    ViewBag.DocumentationTypeId = new SelectList(db.DocumentationTypes, "Id", "DocumentationTypeName", personDocumentation.DocumentationTypeId);
    return View(personDocumentation);
}

查看/表格

@using (Html.BeginForm("Create", "PersonDocumentations", FormMethod.Post, new {enctype = "multipart/form-data" }))
{
    // Form stuff here

    <div class="form-group">
        <input type="submit" value="Create" class="btn btn-lg btn-success" />
    </div>
}

调试时，在提交时，我被重定向到带有route属性的HttpGet Create操作。当相应的Get操作具有路由属性时，我可以提交到Post Action吗？

更新

看着下面的Nkosi回答..我有这个：

[HttpGet]
[Route("CreateDocument/{personId}")]
public ActionResult Create(int personId)
{
    // stuff here
}

[HttpPost]
[Route("CreateDocument")]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Include = "Id,PersonId,DateReceived,DocumentationTypeId,Filepath")] PersonDocumentation personDocumentation)
{
    // stuff here
}

在我的视图页面..要获取HttpGet操作，我有一个按钮链接：

@Html.ActionLink("Create New Documentation", "Create", new {personId = Model.PersonId}, new {@class = "btn btn-info"})

但是，当我将鼠标悬停在按钮上时，我会看到左下角的链接：

http://localhost:xxxxx/CreateDocument?personId=4

不应该是：

http://localhost:xxxxx/CreateDocument/4

当我从HttpPost操作中删除Route属性时，左下角的网址显示为http://localhost:xxxxx/CreateDocument/4

然后，当我点击按钮时，我收到404错误：

Requested Url:  /CreateDocument


public class RouteConfig
{
    public static void RegisterRoutes(RouteCollection routes)
    {
        routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

        routes.MapMvcAttributeRoutes();

        routes.MapRoute(
            name: "Default",
            url: "{controller}/{action}/{id}",
            defaults: new { controller = "PersonInfo", action = "Index", id = UrlParameter.Optional }
        );
    }
}

Answer 1

您正在混合属性和基于约定的路由。

如果在控制器上使用属性路由，则需要全押。使用多个操作时，还必须包含message_deny以进一步区分操作路径。

[Http{Verb}]

这也假设没有public class PersonDocumentationsController : Controller { [HttpGet] public ActionResult Index() { //... } //GET CreateDocument/4 [HttpGet] [Route("CreateDocument/{personId:int}")] public ActionResult Create(int personId) { //... } //POST CreateDocument/4 [HttpPost] [Route("CreateDocument/{personId:int}")] [ValidateAntiForgeryToken] public ActionResult Create([Bind(Include = "Id,PersonId,DateReceived,DocumentationTypeId,Filepath")] PersonDocumentation personDocumentation) { //... } }应用于控制器。

现在当你打电话

RoutePrefix

在@Html.BeginForm("Create", "PersonDocumentations", FormMethod.Post, new {enctype = "multipart/form-data" }))视图中，它将映射到正确的操作。

PersonDocumentationsController.Create

对于操作链接，您还需要包含所需的控制器

POST CreateDocument/4

哪个应映射到

@Html.ActionLink("Create New Documentation", "Create", "PersonDocumentations" , new {personId = Model.PersonId}, new {@class = "btn btn-info"})

参考Attribute Routing in ASP.NET MVC 5

使用RouteAttribute时无法提交表单，提交错误操作

1 个答案: